我有兩個哈希值,一個看起來是這樣的:比較兩個哈希值,然後再刪除,如果ID不存在
{:id => "[email protected]",
:name => "Shellys Shoes",
:lat => 51.5145683289,
:lng => -0.1262439936}
這只是一個紀錄,有大約80%,
第二哈希我有是:
{"id":"[email protected]",
"lat":51.5123596191,
"lng":-0.1244800016}
上面的散列又只是一個記錄,但它是HASH以上通過不返回所有的記錄,只有有效的,我想要做一個API會後的產物比較t運算散列與底部一個,並刪除不存在於底部散列任何記錄,
,例如,如果ID:[email protected]不在所述第二散列然後刪除記錄,
我可以比較哈希,但不知道如何刪除ID不存在?
謝謝你們!
編輯: 這些返回值....
{"points":[{"id":"[email protected]","lat":51.5128250122,"lng":-0.1246550009},{"id":"[email protected]","lat":51.5123596191,"lng":-0.1243880019},{"id":"[email protected]","lat":51.5123596191,"lng":-0.1244800016},{"id":"[email protected]","lat":51.5130996704,"lng":-0.1248089969},{"id":"[email protected]","lat":51.5133934021,"lng":-0.1245559976},{"id":"[email protected]","lat":51.5133934021,"lng":-0.1245559976},{"id":"[email protected]","lat":51.5122642517,"lng":-0.1244129986},]}
這是原來的格式:
[ { :id => "SG_2Km6LX3tEcFwx24eo[email protected]",
:name => "French Connection Group Plc",
:lat => 51.5130157471,
:lng => -0.1237210035
}]
當你說你有大約80條記錄,這些在散列數組/列表? – mikej
嘿我會編輯上面顯示!謝謝! –
返回的值是JSON格式,您需要解析它以將其用作散列。 – karatedog