' just add a loop and some checkings
Sub t()
Dim heightA As Long
Dim heightB As Long
Dim height As Long
Dim i As Long
heightA = Cells(Rows.Count, 1).End(xlUp).Row
heightB = Cells(Rows.Count, 2).End(xlUp).Row
If heightA < heightB Then
height = heightA
Else
height = heightB
End If
If height > 1 Then
For i = 1 To height
Range("A" & i).Font.Bold = False
''Replace the formula with the full string
Range("A" & i) = Range("A" & i).Value
'Find the starting position of the string in B within the string produced by the formula
If Range("B" & i).Value <> "" Then
myPos = InStr(1, Range("A" & i).Value, Range("B" & i).Value, 1)
If myPos > 0 Then
'Bold the string from B column
Range("A" & i).Characters(myPos, Len(Range("B" & i).Value)).Font.Bold = True
End If
End If
Next i
End If
End Sub
EDIT:在格式 MASTER_STR使用位置時,SUBSTR1,POS1(START-END),SUBSTR2,POS2,e.t.c.
Sub t()
Dim heightA As Long
Dim heightB As Long
Dim height As Long
Dim i As Long
Dim length As Long
Dim tmp
Dim width As Long
heightA = Cells(Rows.Count, 1).End(xlUp).Row
heightB = Cells(Rows.Count, 2).End(xlUp).Row
If heightA < heightB Then
height = heightA
Else
height = heightB
End If
If height > 1 Then
For i = 1 To height
Range("A" & i).Font.Bold = False
''Replace the formula with the full string
Range("A" & i) = Range("A" & i).Value
'Find the starting position of the string in B within the string produced by the formula
width = Cells(i, Columns.Count).End(xlToLeft).Column
If width >= 3 Then
For j = 3 To width Step 2
If Cells(i, j).Value <> "" Then
tmp = Split(Cells(i, j).Value, "-")
myPos = CLng(tmp(0))
length = CLng(tmp(1)) - myPos + 1
'myPos = InStr(1, Range("A" & i).Value, Range("B" & i).Value, 1)
If myPos > 0 Then
'Bold the string from B column
Range("A" & i).Characters(myPos, length).Font.Bold = True
End If
End If
Next j
End If
Next i
End If
End Sub
樣例輸入
ABCDEFG A 1-1 C 3-5
ABCDEFG A 1-1 C 3-3
真棒,這就是完美!非常感謝Larry! – lqdo
如果您需要關於代碼的任何解釋,您可以評論/聊天我 – Larry
我這麼認爲,但是如果列C,E ......以及之後已經給出了位置,那麼爲什麼我們需要列B,D .. – Larry