如何比較數組的元素並根據條件進行合併？

Question

我有以下樣本陣列（原始陣列具有多於200種元素）

var array = [ 
    { 
    "clientid": "ID000002", 
    "accesstoken": "pllALEl3TlwLL9hHP938H", 
    "groupname": "ABC", 
    "ancestorid": "8982857550", 
    "stroyid": [ 
     "IGN-EXM-001-PDF", 
     "IGN-EXM-002-PDF" 
    ] 
    }, { 
    "clientid": "ID000002", 
    "accesstoken": "pllALEl3TlwpHOD4aTP38H", 
    "groupname": "EFG", 
    "ancestorid": "4705872914", 
    "stroyid": [ 
     "APP-ENE-FIE-CON", 
     "APP-ENE-ASS-INS", 
     "APP-ENE-ASS-CAR", 
     "APP-ENE-MAT-REA" 
    ] 
    }, { 
    "clientid": "ID000002", 
    "accesstoken": "pllALEl3TlwLL9hHP938H", 
    "groupname": "ABC", 
    "ancestorid": "8982857550", 
    "stroyid": [ 
     "IGN-EXM-001-ZIP", 
     "IGN-EXM-002-ZIP" 
    ] 
    } 
] 

條件=如果（客戶端ID & &祖先ID相同，則合併storyid），因此，輸出應爲這樣的：

[{ 
    "clientid": "ID000002", 
    "accesstoken": "pllALEl3TlwLL9hHP938H", 
    "groupname": "ABC", 
    "ancestorid": "8982857550", 
    "stroyid": [ 
    "IGN-EXM-001-PDF", 
    "IGN-EXM-002-PDF", 
    "IGN-EXM-001-ZIP", 
    "IGN-EXM-002-ZIP" 

    ] 
}, { 
    "clientid": "ID000002", 
    "accesstoken": "pllALEl3TlwpHOD4aTP38H", 
    "groupname": "EFG", 
    "ancestorid": "4705872914", 
    "stroyid": [ 
    "APP-ENE-FIE-CON", 
    "APP-ENE-ASS-INS", 
    "APP-ENE-ASS-CAR", 
    "APP-ENE-MAT-REA" 
    ] 
}] 

請幫我用JavaScript代碼來實現這一點。

Answer 1

您可以使用波紋管與原始storyId陣列合併storyId沒有重複，然後取代它：

if(array[0].clientid == array[1].clientid && array[0].ancestorid == array[1].ancestorid){ 
var c = array[0].stroyid.concat(array[1].stroyid.filter(function (item) { 
    return array[0].stroyid.indexOf(item) < 0; 
})); 
} 

Answer 2

const myArray = [ 
 
    { clientid: 1, ancestorid: 1, stroyid: ['a', 'b', 'c'] }, 
 
    { clientid: 1, ancestorid: 1, stroyid: ['a', 'b', 'd', 'e'] }, 
 
]; 
 

 
const newArray = myArray.reduce((newArray, entry) => { 
 
    // Find if there is a duplicate in the new array 
 
    const duplicate = newArray.find(newEntry => (
 
    entry.clientid === newEntry.clientid && entry.ancestorid === newEntry.ancestorid 
 
)); 
 

 
    // If there is a duplicate, merge their stroyids 
 
    if (duplicate) { 
 
    const cleanIDs = entry.stroyid.filter(id => !duplicate.stroyid.includes(id)); 
 
    duplicate.stroyid = duplicate.stroyid.concat(cleanIDs); 
 
    } 
 
    else newArray.push(entry); // Else, add the entire entry 
 

 
    return newArray; 
 
}, []); 
 

 
console.log(newArray);

Answer 3

一個可以處理這個辦法是遍歷您的數組並將結果添加到基於合併條件的唯一組合的Map中。類似於ID的連接應該起作用。

如果地圖在此條件下已經有一個對象作爲其關鍵字，我們將當前項目與該值合併，否則我們將其添加。

您的代碼的一個瓶頸是，您還需要對這些對象進行深度合併，這些對象在JavaScript中本地不受支持，超出了此問題的範圍。您可以檢查出this SO thread。

下面是一個例子（我使用deepmerge庫合併）：如果需要

var array=[{clientid:"ID000002",accesstoken:"pllALEl3TlwLL9hHP938H",groupname:"ABC",ancestorid:"8982857550",stroyid:["IGN-EXM-001-PDF","IGN-EXM-002-PDF"]},{clientid:"ID000002",accesstoken:"pllALEl3TlwpHOD4aTP38H",groupname:"EFG",ancestorid:"4705872914",stroyid:["APP-ENE-FIE-CON","APP-ENE-ASS-INS","APP-ENE-ASS-CAR","APP-ENE-MAT-REA"]},{clientid:"ID000002",accesstoken:"pllALEl3TlwLL9hHP9n",groupname:"ABC",ancestorid:"8982857550",stroyid:["IGN-EXM-001-ZIP","IGN-EXM-002-ZIP"]}]; 
 
    
 
const map = new Map(); 
 
const mergeKey = ({ clientid, ancestorid }) => `${clientid}${ancestorid}`; 
 

 
for (const item of array) { 
 
    const key = mergeKey(item); 
 
    if (map.has(key)) { 
 
    map.set(key, deepmerge(map.get(key), item)); 
 
    } else { 
 
    map.set(key, item); 
 
    } 
 
} 
 

 
const merged = Array.from(map.values()); 
 
console.log(merged);

<script src="https://unpkg.com/deepmerge@1.3.2/index.js"></script>

ES5版本：

var array=[{clientid:"ID000002",accesstoken:"pllALEl3TlwLL9hHP938H",groupname:"ABC",ancestorid:"8982857550",stroyid:["IGN-EXM-001-PDF","IGN-EXM-002-PDF"]},{clientid:"ID000002",accesstoken:"pllALEl3TlwpHOD4aTP38H",groupname:"EFG",ancestorid:"4705872914",stroyid:["APP-ENE-FIE-CON","APP-ENE-ASS-INS","APP-ENE-ASS-CAR","APP-ENE-MAT-REA"]},{clientid:"ID000002",accesstoken:"pllALEl3TlwLL9hHP9n",groupname:"ABC",ancestorid:"8982857550",stroyid:["IGN-EXM-001-ZIP","IGN-EXM-002-ZIP"]}]; 
 
    
 
var map = Object.create(null); 
 
function mergeKey(item) { 
 
    return item.clientid + item.ancestorid; 
 
} 
 

 
array.forEach(function(item) { 
 
    var key = mergeKey(item); 
 
    if (map[key]) { 
 
    map[key] = deepmerge(map[key], item); 
 
    } else { 
 
    map[key] = item; 
 
    } 
 
}); 
 

 
var merged = Object.keys(map).map(function(key) { 
 
    return map[key]; 
 
}); 
 
console.log(merged);

<script src="https://unpkg.com/deepmerge@1.3.2/index.js"></script>

Answer 4

使用簡單的Javascript，您可以使用散列表作爲關閉與clientid和ancestorid分組。

stroyid針對唯一值進行過濾。

var array = [{ clientid: "ID000002", accesstoken: "pllALEl3TlwLL9hHP938H", groupname: "ABC", ancestorid: "8982857550", stroyid: ["IGN-EXM-001-PDF", "IGN-EXM-002-PDF", "dupe"] }, { clientid: "ID000002", accesstoken: "pllALEl3TlwpHOD4aTP38H", groupname: "EFG", ancestorid: "4705872914", stroyid: ["APP-ENE-FIE-CON", "APP-ENE-ASS-INS", "APP-ENE-ASS-CAR", "APP-ENE-MAT-REA"] }, { clientid: "ID000002", accesstoken: "pllALEl3TlwLL9hHP9n", groupname: "ABC", ancestorid: "8982857550", stroyid: ["IGN-EXM-001-ZIP", "IGN-EXM-002-ZIP", "dupe"] }], 
 
    result = array.reduce(function (hash) { 
 
     return function (r, a) { 
 
      var key = [a.clientid, a.ancestorid].join('|'); 
 
      if (!hash[key]) { 
 
       hash[key] = { clientid: a.clientid, accesstoken: a.accesstoken, groupname: a.groupname, ancestorid: a.ancestorid, stroyid: a.stroyid }; 
 
       return r.concat(hash[key]); 
 
      } 
 
      hash[key].stroyid = hash[key].stroyid.concat(a.stroyid).filter(function (temp) { 
 
       return function (a) { 
 
        return !temp[a] && (temp[a] = true); 
 
       }; 
 
      }(Object.create(null))); 
 
      return r; 
 
     }; 
 
    }(Object.create(null)), []); 
 
    
 
console.log(result);

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