PHP的 - 回聲html代碼和變量從MySQL查詢

Question

我想從MYSQL打印文章的列表，但我不斷收到錯誤。

while($row = mysql_fetch_assoc($query)){ 
    echo "<article class='post'> 
       <h2><a style='color:#43484d' href='' " .$row['url']. ";</a></h2> 
        <ul class='meta'> 
         <li><span>level :</span> <span style='color:red'>" .$row['Level']. " </span></li> 
         <li><span>Negative votes by visitors :</span> " .$row['negativeVotes']. "</li> 
         <li><span>Positive votes by visitors :</span>" .$row['positiveVotes']. "</li> 
         <li><span style='color:#000; cursor:pointer' class='fa fa-thumbs-o-up'></span></li> 
         <li><span style='color:#000; cursor:pointer' class='fa fa-thumbs-o-down'></span></li> 
        </ul> 
       </article>" 
      } 

    ?> 

我得到這個

Parse error: syntax error, unexpected '}', expecting ',' or ';'.

我做了什麼錯？ 非常感謝！

Answer 1

你錯過了一個分號。

while($row = mysql_fetch_assoc($query)){ 
    echo "<article class='post'> 
       <h2><a style='color:#43484d' href='' " .$row['url']. ";</a></h2> 
        <ul class='meta'> 
         <li><span>level :</span> <span style='color:red'>" .$row['Level']. " </span></li> 
         <li><span>Negative votes by visitors :</span> " .$row['negativeVotes']. "</li> 
         <li><span>Positive votes by visitors :</span>" .$row['positiveVotes']. "</li> 
         <li><span style='color:#000; cursor:pointer' class='fa fa-thumbs-o-up'></span></li> 
         <li><span style='color:#000; cursor:pointer' class='fa fa-thumbs-o-down'></span></li> 
        </ul> 
       </article>"; 
      } 

    ?>