錯誤在我的PHP

-5

[16-Aug-2013 01:38:56 America/Sao_Paulo] PHP Parse error: syntax error, unexpected '}' in /home/lineage/public_html/includes/templates/activate.php on line 21

存檔：錯誤在我的PHP

<?php 
    if (!isset($included) || !$included) exit(); 

    if ($hash->validate($_GET['serial'])) 
     if ($_handlerLoginServer->exec($_queryLogin['activateAccount'],array($_GET['serial'])) > 0) { 
      $account = $_handlerLoginServer->select($_queryLogin['accountSerial'],array($_GET['serial'])); 
      if ($cookie->set("referral")) { 
       if (!$_handlerLoginServer->select($_queryLogin['checkIP'],array($_SERVER['REMOTE_ADDR']))) 
        $_handlerLoginServer->execute($_queryLogin['increaseReferral'],array($cookie->get("referral"))); 
        $playerInfo = $_handlerLoginServer->select($_queryLogin['selectPlayer'],array($cookie->get("referral"))); 
        if ($playerInfo[3] % 10 == 0) { 
         $balance->increase($playerInfo[1],$_config['referralReward']); 
         $log->add($log->format($_lang['log']['referralReward'],array($_config['referralReward'])),$playerInfo[1]); 
        } 
       } 
       $cookie->delete("referral"); 
      } 
      $log->add($_lang['log']['activatedAccount'],$account[0]); 

      $_templatePage->replace("feedback",$_lang['success']['activateAccount']); 
     } else 
      $_templatePage->replace("feedback",$_lang['error']['activateAccount']); 
    } else 
     $_templatePage->replace("feedback",$_lang['error']['serialFormat']); 
?>

來源

2013-08-16 user2688200

扔在4號線 – 2013-08-16 05:01:27

年底開放的花@vinodadhikary你還不如編輯的問題，使它的答案！ – Prasanth

@Prasanth，我在等待一些回答說，至少練習打開和關閉大括號，這是一個很好的編程習慣。僅僅因爲你不需要它（對於一個單獨的線塊，所謂的）並不意味着你必須忽略它，並最終陷入這個混亂。 – vee

在4號線和8，你需要添加一個左括號

更換線4

if ($hash->validate($_GET['serial']))

到

if ($hash->validate($_GET['serial'])) {

變線8

if (!$_handlerLoginServer->select($_queryLogin['checkIP'],array($_SERVER['REMOTE_ADDR'])))

到

if (!$_handlerLoginServer->select($_queryLogin['checkIP'],array($_SERVER['REMOTE_ADDR']))) {

來源

2013-08-16 05:03:21

你添加了一個錯字，所以我編輯了 – 2013-08-16 05:10:21

轉到4號線，並添加一個開放squiggily支架：

<?php 
    if (!isset($included) || !$included) exit(); 

    if ($hash->validate($_GET['serial'])){

來源

2013-08-16 05:02:09

錯誤在我的PHP

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