pycurl無限循環和getopt問題

Question

即時通訊新的編碼和嘗試學習，因爲我去。

我試圖創建一個python腳本，將抓取和打印所有的頭文件中的所有網址在一個txt文件中的URL。

它似乎到達那裏，但我陷入了一個無限循環與網址之一，我不知道爲什麼和由於某種原因，「-h或--help」不會返回usage（）。任何幫助，將不勝感激。

下面是我迄今爲止

#!/usr/bin/python 

import pycurl 
import cStringIO 
import sys, getopt 

buf = cStringIO.StringIO() 
c = pycurl.Curl() 

def usage(): 
    print "-h --help, -i --urlist, -o --proxy" 
    sys.exit() 

def main(argv): 
    iurlist = None 
    proxy = None 
    try: 
     opts, args = getopt.getopt(argv,"hi:o:t",["help", "iurlist=","proxy="]) 
     if not opts: 
     print "No options supplied" 
     print "Type -h for help" 
     sys.exit() 
    except getopt.GetoptError as err: 
     print str(err) 
     usage() 
     sys.exit(2) 

    for opt, arg in opts: 
     if opt == ("-h", "--help"): 
      usage() 
      sys.exit() 
     elif opt in ("-i", "--iurlist"): 
      iurlist = arg 
     elif opt in ("-o", "--proxy"): 
      proxy = arg 
     else: 
      assert False, "Unhandeled option" 

with open(iurlist) as f: 
     iurlist = f.readlines() 
     print iurlist 

try: 
     for i in iurlist: 
      c.setopt(c.URL, i) 
      c.setopt(c.PROXY, proxy) 
      c.setopt(c.HEADER, 1) 
      c.setopt(c.FOLLOWLOCATION, 1) 
      c.setopt(c.MAXREDIRS, 30) 
      c.setopt(c.USERAGENT, 'Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:24.0) Gecko/20100101 Firefox/24.0') 
      c.setopt(c.TIMEOUT, 8) 
      c.setopt(c.CONNECTTIMEOUT, 5) 
      c.setopt(c.NOBODY, 1) 
      c.setopt(c.PROXY, proxy) 
      c.setopt(c.WRITEFUNCTION, buf.write) 
      c.setopt(c.SSL_VERIFYPEER, 0) 
      c.perform() 
      print buf.getvalue() 
      buf.close 

    except pycurl.error, error: 
     errno, errstr = error 
     print 'An error has occurred: ', errstr 

if __name__ == "__main__": 
    main(sys.argv[1:]) 

這是最新的代碼

#!/usr/bin/python 

import pycurl 
import cStringIO 
import sys, getopt 

c = pycurl.Curl() 

def usage(): 
    print "-h --help, -i --urlist, -o --proxy" 
    print "Example Usage: cURLdect.py -i urlist.txt -o http://192.168.1.64:8080" 
    sys.exit() 

def main(argv): 
    iurlist = None 
    proxy = None 
    try: 
     opts, args = getopt.getopt(argv,"hi:o:t",["help", "iurlist=","proxy="]) 
     if not opts: 
     print "No options supplied" 
     print "Type -h for help" 
     sys.exit() 
    except getopt.GetoptError as err: 
     print str(err) 
     usage() 
     sys.exit(2) 

    for opt, arg in opts: 
     if opt in ("-h", "--help"): 
      usage() 
      sys.exit() 
     elif opt in ("-i", "--iurlist"): 
      iurlist = arg 
     elif opt in ("-o", "--proxy"): 
      proxy = arg 
     else: 
      assert False, "Unhandeled option" 

    with open(iurlist) as f: 
     iurlist = f.readlines() 
     print iurlist 

    try: 
     for i in iurlist: 
      buf = cStringIO.StringIO() 
      c.setopt(c.WRITEFUNCTION, buf.write) 
      c.setopt(c.PROXY, proxy) 
      c.setopt(c.HEADER, 1) 
      c.setopt(c.FOLLOWLOCATION, 1) 
      c.setopt(c.MAXREDIRS, 300) 
      c.setopt(c.USERAGENT, 'Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:24.0) Gecko/20100101 Firefox/24.0') 
      c.setopt(c.TIMEOUT, 8) 
      c.setopt(c.CONNECTTIMEOUT, 5) 
      c.setopt(c.NOBODY, 1) 
      c.setopt(c.SSL_VERIFYPEER, 0) 
      c.setopt(c.URL, i) 
      c.perform() 
      print buf.getvalue() 
      buf.close() 
    except pycurl.error, error: 
     errno, errstr = error 
     print 'An error has occurred: ', errstr 

if __name__ == "__main__": 
    main(sys.argv[1:]) 

Answer 1

如果你正在學習，pycurl可能不是最好的選擇。他們假設你熟悉libcurl庫。從http://pycurl.sourceforge.net/：

PycURL是針對一個先進開發商 - 如果你需要幾十個併發，快速和可靠的連接，或上述任何然後PycURL是爲你列出的複雜的功能。

PycURL的主要缺點是它是一個比libcurl相對較薄的層，沒有任何這些不錯的Pythonic類層次結構。這意味着它有一個陡峭的學習曲線，除非您已經熟悉libcurl的C API。

這是他們是如何做到多取：https://github.com/pycurl/pycurl/blob/master/examples/retriever-multi.py

---

要取頭一拉蟒蛇，安裝requests庫，只是做：

for url in list_of_urls: 
    r = requests.get(url) 
    print r.headers 

要處理命令行參數，請使用python附帶的電池中的argparser。

Answer 2

您使用

如果選擇==（「-h 「，」--help「）：

的幫助選項，但

如果選擇在（....）

所有其他選項。 opt要麼是-h要麼是--help，但不是兩者，所以您需要使用in來檢查opt是否也是。