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我想過濾模型的集合,但過濾器似乎只是返回一個對象而不是集合。從我讀過的,在_()中包裝過濾器函數將強制它使用內置在過濾器中的underscore.js,並返回相同的類型。但這似乎並沒有奏效。代碼在下面,有什麼想法?Backbone.js過濾器集合返回一個對象,而不是集合
var clients = this.get('clients')
if (clients instanceof Backbone.Collection) {
console.log('clients is a collection');
} else if (_.isObject(clients)) {
console.log('clients is an object');
} else if (_.isArray(clients)) {
console.log('clients is an array');
} else {
console.log('clients is not known');
}
clients = _(clients.filter(function (client) {
return client.get('case_studies').length;
}));
if (clients instanceof Backbone.Collection) {
console.log('clients is a collection');
} else if (_.isObject(clients)) {
console.log('clients is an object');
} else if (_.isArray(clients)) {
console.log('clients is an array');
} else {
console.log('clients is not known');
}
這是我的輸出:
clients is a collection
clients is an object
工作完美,只是缺少一個小括號最後是sis。 – Mark26855