在mysql中選擇一個值範圍

Question

我如何選擇除MySql查詢中前3行以外的所有行？

$query = mysql_query("SELECT * FROM comments WHERE approved = 1"); 

Answer 1

SELECT * FROM comments WHERE approved = 1 LIMIT 3,SOME_HUGE_NUMBER 

See this post for more info

Answer 2

你想以下：

$query = mysql_query("SELECT * FROM comments WHERE approved = 1"); 
$rowCount = 0; 
while ($row = mysql_fetch_assoc($query)) { 
    $rowCount = $rowCount + 1; 
    // do stuff only if you have reached the third row. 
    if ($rowCount > 3){ 
     // do stuff here 
    } 
} 

Answer 3

$query = mysql_query("SELECT * FROM comments 
            WHERE approved = 1 
            ORDER BY columnName 
            LIMIT 3"); 

要找到COLUMNNAME第三記錄順序使用

$query = mysql_query("SELECT * FROM comments 
            WHERE approved = 1 
            ORDER BY columnName 
            LIMIT 2, 1"); 

查找除第1行之外的所有其他行使用LIMIT 2, total_no_of_rows

如果您不知道total_no_of_rows使用非常大的數字而不是它。

$query = mysql_query("SELECT * FROM comments 
            WHERE approved = 1 
            ORDER BY columnName 
            LIMIT 2, total_no_of_rows");