發送到DB函數不執行

Question

此功能從用戶獲取日期：

function getCCGraduationDate() { 
     ?> 
     <form method="post" action="processor.php"> 
     Graduation Date: <input type="text" name="CCgraduationdate"><br> 
     <input type="submit"> 
     <?php 
    } 

該函數將值發送到一個數據庫，被稱爲processor.php頁：

function sendCCGraduationDate() { 
    $con = mysql_connect("localhost","root","XXXXXX"); 
    if (!$con) 
     { 
    die('Could not connect: ' . mysql_error()); 
     } 
     mysql_select_db("user", $con); 
     $grad = mysql_real_escape_string($_POST['CCGraduationDate'], $con); 
     $sql = "UPDATE profile SET CommunityCollegeGraduationDate='$grad' WHERE userid=$this->user_id"; 
     mysql_query($sql , $con); 

     mysql_close($con); 

    } 

由於某些原因該值未填充到數據庫中。我昨天晚上測試了類似的功能，他們工作，不知道我在這裏錯過了什麼。

Answer 1

請檢查：

FORM CODE：

<input type="text" name="CCgraduationdate"><br> 

PHP代碼：

$grad = mysql_real_escape_string($_POST['CCGraduationDate'], $con); 

你CCgraduationdate在你的形式不等於CCGraduationDate在PHP代碼

如果你沒有得到這樣的錯誤：

Notice: Undefined index: CCGraduationDate /* blah blah blah */ 

然後你可以嘗試在你的PHP代碼的頂部添加：

error_reporting(E_ALL); 

然後看看是否有錯誤出來。

當然，這是改變你的$sql變量的數據後：

$sql = "UPDATE profile SET CommunityCollegeGraduationDate='$grad' WHERE userid=" . $this->user_id; 

Answer 2

假設有用於$this->user_id實際值：

$sql = "UPDATE profile SET CommunityCollegeGraduationDate='$grad' WHERE userid=$this->user_id"; 

// Should be: 

$sql = "UPDATE profile SET CommunityCollegeGraduationDate='$grad' WHERE userid={$this->user_id}"; 

// Or 

$sql = "UPDATE profile SET CommunityCollegeGraduationDate='$grad' WHERE userid= " . $this->user_id; 

- 編輯 -

$sql = "UPDATE profile SET CommunityCollegeGraduationDate='$grad' WHERE userid= " . $this->user_id; 

if (!mysql_query($sql , $con)) 
    die(mysql_error()); 
} 

- 編輯 -

// To avoid case and extra space issues, sanitize your var first 
$grad = trim(strtolower($grad)); 

// You did well to escape 
$grad = mysql_real_escape_string($grad, $con);