通過HTTP POST方法在android系統

它不是DUPLICATE.Link發送JSON對象，已提供的是一個古老的「HTTP客戶端」已api23被刪除通過HTTP POST方法在android系統

我想送JSON對象：

{"emailId":"[email protected]","address":"Naya bans","city":"Noida","pincode":"201301","account_number":"91123546374208","bank_name":"Axis Bank","branch_name":"91123546374208","ifsc_code":"UTI0000879"}

到網址：

http://10digimr.mobimedia.in/api/mobile_retailer/update_profile 我該怎麼做呢？通過post方法？

方法：

POST /api/mobile_retailer/update_profile

強制性KEY：

{"emailId","address"}

REQUEST JSON：

{"emailId":"[email protected]","address":"Naya bans","city":"Noida","pincode":"201301","account_number":"91123546374208","bank_name":"Axis Bank","branch_name":"91123546374208","ifsc_code":"UTI0000879"}

RESPONSE：

{"message":"Mail Send","data":true,"status":200}

來源

2016-04-25 user6092109

你所提到的API是一個GET方法。請向API開發人員提供有關訪問API的正確方法的文檔。我試着通過休息客戶端向它發送一個POSt請求。它給出了一個錯誤。 – crashOveride

可能的重複[如何發送一個JSON對象通過Android的請求？]（http://stackoverflow.com/questions/3027066/how-to-send-a-json-object-over-request-with-android） –

我的不好！寫錯了網址！ – user6092109

定義類AsyncT並使用調用它onCreate方法：

AsyncT asyncT = new AsyncT(); 
asyncT.execute();

類定義：

class AsyncT extends AsyncTask<Void,Void,Void>{ 

     @Override 
     protected Void doInBackground(Void... params) { 

      try { 
       URL url = new URL(""); //Enter URL here 
       HttpURLConnection httpURLConnection = (HttpURLConnection)url.openConnection(); 
       httpURLConnection.setDoOutput(true); 
       httpURLConnection.setRequestMethod("POST"); // here you are telling that it is a POST request, which can be changed into "PUT", "GET", "DELETE" etc. 
       httpURLConnection.setRequestProperty("Content-Type", "application/json"); // here you are setting the `Content-Type` for the data you are sending which is `application/json` 
       httpURLConnection.connect(); 

       JSONObject jsonObject = new JSONObject(); 
       jsonObject.put("para_1", "arg_1"); 

       DataOutputStream wr = new DataOutputStream(httpURLConnection.getOutputStream()); 
       wr.writeBytes(jsonObject.toString()); 
       wr.flush(); 
       wr.close(); 

      } catch (MalformedURLException e) { 
       e.printStackTrace(); 
      } catch (IOException e) { 
       e.printStackTrace(); 
      } catch (JSONException e) { 
       e.printStackTrace(); 
      } 

      return null; 
     } 


    }

來源

2016-05-15 07:19:58

@gothdo你如何處理你從郵件中得到的迴應？ –

通過HTTP POST方法在android系統

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