檢查是否收到消息或跳過它（python 3.4）

Question

我想問如何跳過接收函數。

def client(): 
    try: 
     b = bytes.decode(h.recv(1024)) 
     print("The recieved message : ",b) 
     b1 = str.encode(b) 
     c.sendall(b1) 
     h.sendall(b1) 
     y.sendall(b1) 
    except Exception: 
     pass 
    try: 
     g = bytes.decode(y.recv(1024)) 
     print("The recieved message : ",g) 
     g1 = str.encode(g) 
     c.sendall(g1) 
     h.sendall(g1) 
     y.sendall(g1) 
    except Exception: 
     pass 

所以我需要做的是檢查是否有來自客戶端的消息：

• 如果是的話，打印和發送。
• 如果否，跳過該功能去與其他客戶端進行覈對。

Answer 1

您需要輪詢機制。最簡單的是select

import select 

def client(): 
    sockets, _, _ = select.select([h, y], [], []) 
    # If h or y has data, select exits and returns these sockets 

    for sock in sockets: 
     try: 
      data = sock.recv(1024) 
      if data == '': 
       # sock was disconnected handle that 
       continue 

      # Process data here 
     except Exception: 
      continue