Python：要求用戶輸入5個不同的標記

Question

問題是編寫一個程序，要求用戶輸入5個不同的學生及其標記中的100個。如果用戶試圖輸入一個學生兩次，程序應檢測到這一點，要求他們輸入一個獨特的學生姓名（和他們的標誌）。

我的計劃是..

dictionary = {} 

count = 0 

while count < 5: 
    name = raw_input("Enter your name: ") 
    mark = input("Enter your mark out of 100: ") 
    if name not in dictionary: 
     dictionary[name] = mark 
     count = count + 1 
    else: 
     name = raw_input("Enter a unique name: ") 
     mark = input("Enter the mark out of 100: ") 
     if name not in dictionary: 
      dictionary[name] = mark 
      count = count + 1 

print dictionary 

我的問題是你怎麼循環的東西：代碼，如果用戶仍能保持輸入相同的名稱和標誌？

Answer 1

dictionary = {} 
count = 0 
while count < 5: 
    name = raw_input("Enter your name: ") 
    name = name.strip().lower() # store name in lower case, e.g. aamir and Aamir consider duplicate 
    if not dictionary.get(name): 
     mark = input("Enter your mark out of 100: ") 
     dictionary[name] = mark 
     count += 1 
    else: 
     print "please enter unique name" 

print dictionary 

• 店鋪名稱以小寫使aamir和Aamir都應該考慮複製
• 重複檢查應早於一步Enter your mark進行保存終端用戶一步

Answer 2

你混合input和raw_input，這是一件壞事。通常你在Python 2和input在Python 3使用raw_input的快速和骯髒的方式來解決你的問題是：

dictionary = {} 

count = 0 

while count < 5: 
    name = raw_input("Enter your name: ") 
    mark = raw_input("Enter your mark out of 100: ") 
    if name not in dictionary: 
     dictionary[name] = mark 
     count = count + 1 
    else: 
     print("You already used that name, enter an unique name.") 

print dictionary 

Answer 3

我想你只需要待辦事項這樣的：

dictionary = {} 

count = 0 

while count < 5: 
     name = raw_input("Enter your name: ") 
     mark = input("Enter your mark out of 100: ") 
     if name not in dictionary: 
      dictionary[name] = mark 
      count = count + 1 

print dictionary