C函數在UNIX中複製目錄：文件無法複製

Question

我想在C中編寫一個函數來將目錄的內容複製到另一個目錄。這是我到目前爲止：

void *copydirectory(void *arg1, void *arg2) 
{ 
    int error; 
    struct dirent *direntp; 
    DIR *dirp_source, *dirp_destination; 
    char *source, *destination; 
    copy_t copy; 
    char filename[MAXNAME]; 

    // Set directory arguments 
    source = arg1; 
    destination = arg2; 
    fprintf(stderr, "Source directory is %s and destination directory is %s\n", source, destination); 

    // Open directories 
    if ((dirp_source = opendir(source)) == NULL) 
    { 
     fprintf(stderr, "Failed to open %s\n", source); 
     return 1; 
    } 

    if ((dirp_destination = opendir(destination)) == NULL) 
    { 
     perror("Failed to open destination directory"); 
     return 1; 
    } 

    // Read files in directory 
    while ((direntp = readdir(dirp_source)) != NULL) 
    { 
     copy.tid = pthread_self(); 
     fprintf(stderr, "now at line 64\n"); 

     // Copy source filename 
     if (snprintf(filename, MAXNAME, direntp->d_name) == MAXNAME) 
     { 
     fprintf(stderr, "Input filename %s is too long", direntp->d_name); 
     continue; 
     } 

     fprintf(stderr, "now at line 73\n"); 

     fprintf(stderr, "%s\n", filename); 
     // Open file for reading 
     if ((copy.args[0] = open(filename, R_FLAGS)) == -1) 
     { 
     fprintf(stderr, "Failed to open source file %s: %s\n", filename, strerror(errno)); 
     continue; 
     } 

     // Create destination filename for writing 
     if (snprintf(filename, MAXNAME, "%s", direntp->d_name) == MAXNAME) 
     { 
     fprintf(stderr, "Output filename %s is too long\n", direntp->d_name); 
     continue; 
     } 

     fprintf(stderr, "%s\n", filename); 
     // Open file for writing 
     if ((copy.args[1] = open(filename, W_FLAGS, W_PERMS)) == -1) 
     { 
     fprintf(stderr, "Failed to open destination file %s: %s\n", filename,  strerror(errno)); 
     continue; 
     } 

     if (error = pthread_create((&copy.tid), NULL, copyfilepass, copy.args)) 
     { 
     fprintf(stderr, "Failed to create thread: %s\n", strerror(error)); 
     copy.tid = pthread_self(); 
     } 
    } 

    // Close directory 
    while ((closedir(dirp_source) == -1) && (errno = EINTR)); 

    fprintf(stderr, "Successfully copied all files in directory \n"); 

} 

現在，爲了測試，我只在名爲dir1和dir2的文件夾中有2個目錄。 dir1包含3個文件：file1，file2，file3。 但是，當我編譯和運行代碼，我得到的消息：

./ 
./ 
Failed to open destination file .: is a directory 
Failed to open source file file2: No such file or directory 
Failed to open source file file3: No such file or directory 
../ 
../ 
Failed to open destination file .: is a directory 
Failed to open source file file1: No such file or directory 

任何人有什麼錯什麼建議？

Answer 1

無法打開目標文件：是一個目錄

你看這是因爲你的源目錄中包含的鏈接分別稱爲"."和".."本身和它的父目錄。您應該專門檢查並避免這些條目。

無法打開源文件文件2：沒有這樣的FLE或目錄

你看到這一點，因爲你試圖打開一個名爲進程的當前工作目錄"file2"文件，但不存在 - 您所在的文件位於源目錄中。你需要建立文件名考慮到這一點：

// Copy source filename 
if (snprintf(filename, MAXNAME, "%s/%s", source, direntp->d_name) == MAXNAME)