JAVA嵌套而

Question

我爲我初學Java類中的分配工作循環誤差-should是令人驚訝的簡單。該程序是一個利用嵌套while循環的數學測驗。我遇到了一個程序提前結束的問題。下面是產生問題的塊的代碼：

它應該循環輸入的次數爲NumberOfQuestionsInteger，但是它只循環一次，無論您爲NumberOfQuestionsInteger輸入什麼內容。

該代碼是有點馬虎，因爲我一直在搞一切試圖讓它工作。

編輯：更新，以完整的代碼。

代碼工作當我禁用threeTries循環。

任何幫助將大大apreciated！

import javax.swing.JOptionPane; 
import java.util.Random; //import Random class 

public class HroudaASSN2 { 

public static void main(String[] args) { 
    // TODO Auto-generated method stub 


    String NumberOfQuestions = JOptionPane.showInputDialog("How Many Questions Would You Like To Answer?"); 
    int NumberOfQuestionsInteger = Integer.parseInt(NumberOfQuestions); //Converts string to Integer, I named it NumberOfQuestionsInteger so as to make that clear. 

    int score, threeTries; 
    threeTries = 3; 
    score = 0; 


    while (NumberOfQuestionsInteger > 0) // Allows the program to run until exited. 
     { 

     Random firstNum1 = new Random(); //create an object of Random class 
     int firstNum = firstNum1.nextInt(100) + 1; //generate number between 1 and 100. 

     Random secondNum2 = new Random(); //create an object of Random class 
     int secondNum = secondNum2.nextInt(100) + 1; //generate2 number between 1 and 100. 

      while(threeTries > 0){ 
       String Answer = JOptionPane.showInputDialog("Score :" + score +"\ntries remaining: " + threeTries + "\n\n\n" + firstNum + "+" + secondNum); 
       int AnswerInteger = Integer.parseInt(Answer); //Converts string to Integer. 


        if (AnswerInteger == firstNum + secondNum) 
        { 
         threeTries = 0; 
         JOptionPane.showMessageDialog(null," Correct! \n +5 Points!"); 
         score = score + 5; 
         NumberOfQuestionsInteger = NumberOfQuestionsInteger-1; 
        } 

        else 
        { 
         threeTries = threeTries - 1; 
         NumberOfQuestionsInteger = NumberOfQuestionsInteger-1; 
        } 
      } 
     } 
        /* if (threeTries > 0);{ 
         comment.equals("Please Try Again!"); 
         } 
         else 
          {comment.equals("No Attempts Remaining!"); 
          JOptionPane.showMessageDialog(null," Wrong! \n -1 Point! \n Please Try Again!"); 
          score = score--; } */ 




} 
     } 

Answer 1

您需要：

1. 遞減NumberOfQuestionsInteger在外環所以在內環移動

   NumberOfQuestionsInteger = NumberOfQuestionsInteger - 1; 
   

   從if小號

   到外環。每個內環前可嘗試的

2. 復位號碼，以便移動

   threeTries = 3; 
   

   你外環

3. 開始你並不需要Random類的一些實例。一個就足夠了。也不要在循環中初始化它。循環之前做到像

   Random rand = new Random(); 
   while(NumberOfQuestionsInteger > 0){ 
       int firstNum = rand.nextInt(100) + 1; 
       int secondNum= rand.nextInt(100) + 1; 
       //... 
   } 
   

Answer 2

threeTries = 3; 
while(threeTries > 0){ 
    String Answer = JOptionPane.showInputDialog("Score :" + score +"\ntries remaining: " + threeTries + "\n\n\n" + firstNum + "+" + secondNum); 
       int AnswerInteger = Integer.parseInt(Answer); //Converts string to Integer. 
       if (AnswerInteger == firstNum + secondNum) 
       { 
        threeTries = 0; 
        JOptionPane.showMessageDialog(null," Correct! \n +5 Points!"); 
        score = score + 5; 
       } 

       else 
       { 
        threeTries = threeTries - 1; 
       } 
} 
NumberOfQuestionsInteger = NumberOfQuestionsInteger-1;