2009-06-03 52 views
0

我想使用XSL文件更改BDC列表webpart的數據庫列名稱。使用XSLT編輯Sharepoint BDC webpart的列標題

我的SQL查詢是"Select BATCH_ID...",我想使用XSL將該列名稱"BATCH_ID"更改爲"ID"。我也想知道$ColName_0如何填充值'BATCH_ID'

dvt.headerfield模板裏面是排序和添加排序菜單。但在調用模板之前填充$ColName_0。 XSLT代碼如下:

<xsl:stylesheet 
    version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:ddwrt="http://schemas.microsoft.com/WebParts/v2/DataView/runtime" 
    xmlns:asp="http://schemas.microsoft.com/ASPNET/20" 
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" 
    xmlns:SharePoint="Microsoft.Sharepoint.WebControls" 
    exclude-result-prefixes="xsl msxsl ddwrt" 
> 
    <xsl:output method="xml" indent="yes"/> 
    <xsl:param name="dvt_partguid" /> 
    <xsl:param name="ColName_0"></xsl:param> 

    <xsl:template name="dvt.headerfield"> 
    <xsl:param name="fieldname" /> 
    <xsl:param name="fieldtitle" /> 
    <xsl:param name="displayname" /> 
    <xsl:param name="fieldtype">0</xsl:param> 

    <table CtxNum="1" cellspacing="0" class="ms-unselectedtitle" onmouseover="OnMouseOverAdHocFilter(this, '{concat($displayname,$fieldname, $fieldtype, $dvt_partguid)}')"> 
     <tr> 
     <td width="100%" class="ms-vb" nowrap=""> 
      <a> 
      <xsl:attribute name="href">javascript: <xsl:value-of select="ddwrt:GenFireServerEvent(('dvt_sortfield;dvt_sortdir'))" />;</xsl:attribute> 
      <xsl:value-of select="$fieldtitle"/> 
      </a>     
     </td> 
     <td> 
      <img src="/_layouts/images/blank.gif" width="13" style="visibility: hidden" alt="" /> 
     </td> 
     </tr> 
    </table> 
    </xsl:template> 

    <xsl:template match="/"> 
    <xsl:call-template name="dvt_1" /> 
    </xsl:template> 

    <xsl:template name="dvt_1"> 
    <xsl:variable name="dvt_StyleName">Table</xsl:variable> 

    <table id="BdwpRows" border="0" width="100%" cellpadding="2" cellspacing="0"> 
     <tr valign="top"> 
     <th class="ms-vh" width="1" /> 
     <th class="ms-vh" align="left"> 
      <xsl:call-template name="dvt.headerfield" ddwrt:atomic="1"> 
      <xsl:with-param name="fieldname">@BATCH_ID</xsl:with-param> 
      <xsl:with-param name="fieldtitle"> 
       <xsl:value-of select="$ColName_0" /> 
      </xsl:with-param> 
      <xsl:with-param name="displayname"> 
       <xsl:value-of select="$ColName_0" /> 
      </xsl:with-param> 
      <xsl:with-param name="fieldtype">text</xsl:with-param> 
      </xsl:call-template> 
     </th> 
     </tr>   
    </table> 
    </xsl:template> 
</xsl:stylesheet> 
+0

您可以發佈一些示例xml的xslt工作? – 2009-06-03 16:46:30

回答

0

不知道這是最好的方式,但這裏是我是如何做的:

變化:

<xsl:with-param name="fieldname">@BATCH_ID</xsl:with-param> 
    <xsl:with-param name="fieldtitle"> 
     <xsl:value-of select="$ColName_0" /> 
    </xsl:with-param> 
    <xsl:with-param name="displayname"> 
     <xsl:value-of select="$ColName_0" /> 
    </xsl:with-param> 
<xsl:with-param name="fieldtype">text</xsl:with-param> 

要:

<xsl:with-param name="fieldname">@BATCH_ID</xsl:with-param> 
    <xsl:with-param name="fieldtitle"> 
     ID 
    </xsl:with-param> 
    <xsl:with-param name="displayname"> 
     <xsl:value-of select="$ColName_0" /> 
    </xsl:with-param> 
<xsl:with-param name="fieldtype">text</xsl:with-param>