jQuery對象數據奇偶值到在選擇奇數作爲選項值顯示，即使選擇文本

Question

g_regions = ["USD", "North America", "EUR", "Europe", "GBP", "United Kingdom", "USD", "Asia & Pacific", "USD", "Australasia", "USD", "South America", "USD", "Africa"]; 

以上數值使用jQuery的是顯示在select dropdown。

爲如：像這樣

<select> 
    <option value="USD">North America</option> 
    <option value="EUR">Europe</option> 
    <option value="GBP">United Kingdom</option> 
    <option value="USD">Asia & Pacific</option> 
    <option value="USD">Australasia</option> 
    <option value="USD">South America</option> 
    <option value="USD">Africa</option> 
</select> 

Answer 1

輸出在這裏，你有一個解決方案

$('body').append('<select />'); 
 

 
var g_regions = ["USD", "North America", "EUR", "Europe", "GBP", "United Kingdom", "USD", "Asia & Pacific", "USD", "Australasia", "USD", "South America", "USD", "Africa"]; 
 

 
for(var i=0; i<g_regions.length; i=i+2){ 
 
    $('select').append(`<option value="${g_regions[i]}">${g_regions[i+1]}</option>`); 
 
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

環路通過與step increment of 2 &陣列去再附加option到select。

我用ES6版本與backtick而不是單引號或雙引號& ${}。

${}用於分配值，在花括號裏面你需要一個變量。

參考： - JavaScript-Template_literals

希望這會幫助你。