彙編程序

Question

我想在Assembly中創建一個程序，它將從鍵盤讀取一個字符串，然後將每個字母轉換爲另一個表格，然後將其存儲在[201]的表格中。在[200]我有一個字符串的char計數器。以下是我所做的：

mov [0300h],88h  ;thats the table that I want to convert to.(only 3 digits) 

mov [0301h],83h 

mov [0302h],0CEh 


mov ah,01h      ;insert string 
int 81h     


mov di,01h     

start: 
mov al,[di] 
cmp al,00h   ;not 
    sure about that. last char of string 
    should be /0. 

je end     
mov [0200h],di ;char counter.  
inc di 

mov bx,0300h  
sub al,041h 
    ;convert char 
xlat 
mov [di+01ffh],al 
    ;store converted char to 201... 

loop start 

end: 

**int 81h** 
;reads chars until <cr> from keyboard.Starting address of input data buffer    ES:DI+1 

由於某些原因，在我的程序結束時DI值爲0900。任何想法，爲什麼它不工作，或任何想法，我可以通過任何其他方式？非常感謝。

Answer 1

mov al,[di] 

不應該在這裏向輸入緩衝區添加偏移量嗎？

Answer 2

它打破洙..看看本作爲例（它認爲FN int81的1讀取一個char不知道實際的界面。）：

some_table: db 88h, 83h, CEh 
result:  db ??(128) // can't recall the syntax 

push ds 
pop es 
lea bx, some_table 
lea di, result // for stosb to work 

start: 
mov ah,01h      ;//insert string 
int 81h     
cmp al, 0Ah // enter in linux (or it's 0Dh?) 
je end     
sub al, 'A' // what do you mean by "convert to char"? it's already a char. and what happens if it's larger than 'C'? 
xlat 
stosb 
jmp start 
end: