用Spring來保護REST網址

Question

我有一個可以運行的Spring REST網絡服務，並且想爲它添加基本的身份驗證。控制器方法具有正常的URL和附加到它們的HTTP方法註釋。爲了增加安全性，我做兩件事情

1）彈簧security.xml文件添加到它看起來像WEB-INF文件夾：

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns:security="http://www.springframework.org/schema/security" 
     xsi:schemaLocation="http://www.springframework.org/schema/beans 
      http://www.springframework.org/schema/beans/spring-beans-3.1.xsd 
      http://www.springframework.org/schema/security 
      http://www.springframework.org/schema/security/spring-security-3.1.xsd"> 


    <security:http auto-config="true"> 
      <security:http-basic /> 
      <security:intercept-url pattern="/*" access="ROLE_USER" /> 
    </security:http> 

    <security:authentication-manager> 
     <security:authentication-provider> 
     <security:user-service> 
     <security:user name="spring" password="spring" authorities="ROLE_USER" /> 
     </security:user-service> 
     </security:authentication-provider> 
    </security:authentication-manager> 

</beans> 

2）配置Spring Security在web.xml爲：

<?xml version="1.0" encoding="UTF-8"?> 
<web-app id="WebApp_ID" version="2.4" 
    xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> 

    <servlet> 
     <servlet-name>spring</servlet-name> 
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 

    <filter> 
     <filter-name>springSecurityFilterChain</filter-name> 
     <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> 
    </filter> 

    <servlet-mapping> 
     <servlet-name>spring</servlet-name> 
     <url-pattern>/</url-pattern> 
    </servlet-mapping> 

    <listener> 
     <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
    </listener> 

    <context-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value> 
      /WEB-INF/spring-security.xml 
     </param-value> 
    </context-param> 

    <filter-mapping> 
     <filter-name>springSecurityFilterChain</filter-name> 
     <url-pattern>/*</url-pattern> 
    </filter-mapping> 

</web-app> 

3）彈簧控制器：

package com.sample.main; 

import java.util.ArrayList; 
import java.util.Iterator; 
import java.util.List; 

import org.springframework.stereotype.Controller; 
import org.springframework.web.bind.annotation.PathVariable; 
import org.springframework.web.bind.annotation.RequestBody; 
import org.springframework.web.bind.annotation.RequestMapping; 
import org.springframework.web.bind.annotation.RequestMethod; 
import org.springframework.web.bind.annotation.ResponseBody; 

import com.sample.employee.Employee; 

@Controller 
public class EmpController 
{ 
    List<Employee> list = new ArrayList<Employee>(); 

    @RequestMapping(value = "/getEmp/{emp}", method = RequestMethod.GET) 
    public @ResponseBody Employee getEmployee(@PathVariable("emp") int empid) { 
     System.out.println("meet getEmp"); 
     for (Iterator<Employee> iterator = list.iterator(); iterator.hasNext();) { 
      Employee emp = (Employee) iterator.next(); 
      if(emp.getEmpId()==empid) { 
       return emp; 
      } 
     } 
     return new Employee(); 
    } 
} 

4）的applicationContext.xml

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
      http://www.springframework.org/schema/beans/spring-beans-3.1.xsd 
      http://www.springframework.org/schema/context 
      http://www.springframework.org/schema/context/spring-context-3.1.xsd 
      http://www.springframework.org/schema/mvc 
      http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd"> 

    <!-- Activates various annotations to be detected in bean classes --> 
    <context:annotation-config /> 

    <!-- Scans the classpath for annotated components that will be auto-registered as Spring beans. 
    For example @Controller and @Service. Make sure to set the correct base-package--> 
    <context:component-scan base-package="com.sample" /> 

    <!-- Configures the annotation-driven Spring MVC Controller programming model. 
    Note that, with Spring 3.0, this tag works in Servlet MVC only! --> 
    <mvc:annotation-driven /> 

</beans> 

5）爲spring-servlet.xml

<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:p="http://www.springframework.org/schema/p" 
     xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
     http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 
     http://www.springframework.org/schema/context 
     http://www.springframework.org/schema/context/spring-context-3.0.xsd 
       http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> 

</beans> 

我已經上傳完整申請： http://www.javaexperience.com/wp-content/uploads/2012/12/SpringWebServiceSecurity.zip

配置springSecurityFilterChain後，我開始變得對REST的URL 404個錯誤頁面中的應用。任何想法...

Answer 1

嘗試更改調度程序servlet的url-mapping以處理所有請求。

的web.xml

<servlet> 
    <servlet-name>spring</servlet-name> 
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
    <load-on-startup>1</load-on-startup> 
</servlet> 

<servlet-mapping> 
    <servlet-name>spring</servlet-name> 
    <url-pattern>/*</url-pattern> 
</servlet-mapping> 

另外在安全配置更改安全過濾intercept-url-pattern來處理所有的請求。這可以在工作後調整。

彈簧的security.xml

<security:http auto-config="true"> 
     <security:http-basic /> 
     <security:intercept-url pattern="/**" access="ROLE_USER" /> 
</security:http>