格式輸出Itertools.Products

Question

我是新來的Python和編碼（昨晚）。我需要爲輸出生成具有特定格式的大量itertools產品。我可以用產生的組合，

import itertools 
s=[ ['CPT1','OTHERCPT1','OTHERCPT2','OTHERCPT3','OTHERCPT4','OTHERCPT5','OTHERCPT6','OTHERCPT7','OTHERCPT8','OTHERCPT9','OTHERCPT10','CONCURR1','CONCURR2','CONCURR3','CONCURR4','CONCURR5','CONCURR6','CONCURR7','CONCURR8','CONCURR9','CONCURR10'], ['15756','15757','15758','43496','49006','20969','20955','20956','20957','20962','20970','20972','20973'],['CPT1','OTHERCPT1','OTHERCPT2','OTHERCPT3','OTHERCPT4','OTHERCPT5','OTHERCPT6','OTHERCPT7','OTHERCPT8','OTHERCPT9','OTHERCPT10','CONCURR1','CONCURR2','CONCURR3','CONCURR4','CONCURR5','CONCURR6','CONCURR7','CONCURR8','CONCURR9','CONCURR10'], ['15756','15757','15758','43496','49006','20969','20955','20956','20957','20962','20970','20972','20973']] 
x=list(itertools.product(*s)) 
print x 

但是輸出顯示爲這樣：

('CPT1', '15756', 'CPT1', '15756'), ... etc. 

我想它顯示：

SELECT IF(CPT1='15756' AND CPT1='15756'). 
SELECT IF(...). 
etc. 

感謝您的幫助！

Answer 1

你應該使用字符串格式化（https://docs.python.org/2/library/string.html）

import itertools 
s = [[...first list...],[...second list...]] 
for p in itertools.product(*s): 
    print("SELECT IF(CPT1='{}' AND CPT1='{}').".format(*p))