如何從下面的代碼中動態發佈值

Question

如何動態地從下面的代碼 我使用下面的代碼

<?php 
$epages_sql=mysql_query("select * from epages"); 
while($epapers=mysql_fetch_array($epapers_sql)) 
{ 
?> 

<table> 
<tr bgcolor="#FFCCFF"> 
    <td width="40%" height="30"><span class="style9"><?php echo $epapers['epage']; ?></span><input type="hidden" name="page_<?php echo $epapers['id']; ?>" value="<?php echo $epapers['epage']; ?>" /></td> 

    <td width="30%"><input type="file" name="file_<?php echo $epapers['id']; ?>" /></td> 

    <td width="30%"><input type="submit" name="submit_<?php echo $epapers['id']; ?>" value="Upload" class="btn_style"/></td> 
</tr> 

<tr bgcolor="#FFCCFF"><td height="20"></td><td></td><td></td></tr> 
</table> 
<?php 
} 
?> 

<?php 
$epages_sql=mysql_query("select * from epages"); 
while($epapers=mysql_fetch_array($epapers_sql)) 
{ 
if(isset($_POST['???'])) { 
$name=$_POST['???']; 
} 
} 
?> 
How to post this values from the above code in ???what can i use ? 

請幫助我如何解決這個問題

Answer 1

嘗試後的值這一點，使用表格前，在下面開始表，併到形式

<?php 
$epages_sql=mysql_query("select * from epages"); 
while($epapers=mysql_fetch_array($epapers_sql)) 
{ 
?> 
<form name="myform" method="post" action="[youractionpage_name]"> 
<table> 
<tr bgcolor="#FFCCFF"> 
       <td width="40%" height="30"><span class="style9"><?php echo $epapers['epage']; ?></span><input type="hidden" name="page_<?php echo $epapers['id']; ?>" value="<?php echo $epapers['epage']; ?>" /></td> 

       <td width="30%"><input type="file" name="file_<?php echo $epapers['id']; ?>" /></td> 


    <td width="30%"><input type="submit" name="submit_<?php echo $epapers['id']; ?>" value="Upload" class="btn_style"/></td> 
      </tr> 

      <tr bgcolor="#FFCCFF"><td height="20"></td><td></td><td></td></tr> 
</table> 
</form> 
<?php 
} 
?>