爲什麼這個PHP fgetcsv（）僅顯示csv的某些部分？

Question

我有這個PHP：

$handle = fopen($_FILES["csvfile"]["tmp_name"], "r"); 

while (($data = fgetcsv($handle, 5000, ",", '"')) !== FALSE) { 
    echo "<pre>"; 
    print_r($data); 
    echo "<pre>"; 
} 

<form method="post"> 
<input type="file" name="csvfile"> 
<input type="submit> 

的CSV是由HTML <input type="file">提供。現在它正在打印只有第一個值和逗號或每行的數組，而不是打印出每行的十一個數組的數組。我知道它做正確的事情，但不知何故搞亂了我的代碼，無法弄清楚我做了什麼。

這裏是CSV的例子：

"lorem","ipsum","dolor","sit","amet","consectetuer","adipiscing","elit","sed ","diam","nonummy", 

Answer 1

在你貼我得到一個不錯的格式化的結果相同的代碼

file_put_contents('tmp.tmp', 
'"lorem","ipsum","dolor","sit","amet","consectetuer","adipiscing","elit","sed ","diam","nonummy", 
"1lorem","1ipsum","1dolor","1sit","amet","consectetuer","adipiscing","elit","sed ","diam","nonummy", 
'); 

$handle = fopen("tmp.tmp", "r"); 

while (($data = fgetcsv($handle, 5000, ",", '"')) !== FALSE) { 
    echo "<pre>"; 
    print_r($data); 
    echo "<pre>"; 
} 

我得到：

陣列 （ [ 0] => lorem [1] => ipsum [2] => dolor [3] =>坐下 [4] =>阿梅特 [5] => consectetuer [6] => adipiscing [7] => ELIT [8] => sed的 [9] =>直徑 [10] => nonummy [11] => ）

你很可能在別的地方做錯了什麼，而不是注意到它。