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SELECT sum(sum(DATEDIFF(DAY,LeaveBreakup.StartDate,LeaveBreakup.EndDate)+1)) AS totalNoOfDays,
LeaveApplication.Id,
LeaveBreakup.StartDate,
LeaveBreakup.EndDate,
LeaveApplication.ReasonForLeave,
LeaveApplication.ProcessorComment,
Team.Name,
LeaveTypeDetail.Name
FROM LeaveApplication
INNER JOIN Employee ON LeaveApplication.Employee=Employee.Id
INNER JOIN Team ON Employee.Team=Team.Id
INNER JOIN LeaveBreakup ON LeaveApplication.Id=LeaveBreakup.LeaveApplication
INNER JOIN LeaveTypeDetail ON LeaveBreakup.LeaveType=LeaveTypeDetail.LeaveType
WHERE Employee.Team=5
AND LeaveStatus!=0
AND LeaveBreakup.StartDate BETWEEN '01-01-2016' AND '01-31-2016'
AND LeaveBreakup.WhichHalf=0
GROUP BY LeaveApplication.Id,
LeaveBreakup.StartDate,
LeaveBreakup.EndDate,
LeaveApplication.ReasonForLeave,
LeaveApplication.ProcessorComment,
Team.Name,
LeaveTypeDetail.Name
ORDER BY LeaveBreakup.StartDate
你爲什麼要sum'sum'?這是錯誤。 – HoneyBadger
你不需要那些2 SUM在開始SUM(blah)+1 – Mihai
我只是想提前感謝那個列'totalNoOfDays' – akash