jQuery的.append（函數（指數，HTML）{...}）問題

Question

比方說，我們有這個不明 DIV

<div class="class-occurs-many-times-on-page">foo</div> 

，我們希望把後馬上包含幾十個其他不明DIV或幾百SPAN元素：

<div class="a-class-that-occurs-many-times-on-page">foo</div> 
<div class="another-class-that-occurs-many-times-on-page"> 
     <span class="latin">lorem</span><span class="latin">ipse</span> 
     <span class="swedish-chef">føø</span><span class="swedish-chef">bår</span> 
     . 
     . 
     . 
     <span>...</span> 
</div> 

而且我們添加的第一個身份不明的DIV和要添加的SPAN容器DIV這樣：

values = [{word: "lorem", cls: "latin"}, {word: "ipse", cls: "latin"}, 
{word:"føø",cls:"swedish-chef"}, {word:"bår",cls:"swedish-chef"}]; 

$("#" + someParentElement).append(
    $("<div></div>").addClass("a-class-that-occurs-many-times-on-page").text("foo").after(

      $("<div></div>").addClass("another-class-that-occurs-many-times-on-page").append(
       function(index, html){      
        // how to wrap each value in the values array in a span 
        // and inject each of those spans into this DIV? 

       } 
      ) 

    ) 


); 

這種方法是否可行？如果是這樣，如果目標是將數組中的每個值都包含在.append（）方法調用中，那麼函數在值數組的每次迭代中都必須做些什麼SPAN並將該跨度注入容器中？

感謝

Answer 1

values = [{word: "lorem", cls: "latin"}, {word: "ipse", cls: "latin"}, {word:"føø",cls:"swedish-chef"}, {word:"bår",cls:"swedish-chef"}], 
len = values.length, 
$ctn = $('<div/>', { 
    class: 'another-class-that-occurs-many-times-on-page' 
}), 
buildarr = []; 

while(len--){ 
    buildarr.push('<span>'); 
    buildarr.push(values[len].word); 
    buildarr.push(values[len].cls); 
    buildarr.push('</span>'); 
} 

$ctn.append(buildarr.join('')).appendTo(document.body); 

這僅僅是一個建議，你一樣可以完成這個任務種類。它假設我們必須填充陣列的順序是不相關的（通過循環以最快的方式，reversed while）。如果訂單很重要，請使用standard for loop。