如何爲兩個按鈕創建不同的uiactionsheet？

Question

嗨，我在這裏開發小應用程序。在子類屏幕中，我有兩個按鈕。當我按下第一個按鈕時，它會顯示四個操作表。當我按下第二個按鈕時，它將顯示五個操作表。我成功地展示了它。但我不能設置五個動作表的第二個按鈕動作。在我的代碼中，當我按下第一個動作表的第二個按鈕時，它將啓動第一個動作表的第一個按鈕。在這裏，我想爲各個操作表設置操作。請幫助我。這裏是我的代碼是

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { 
if (indexPath.row == 0) 
{ 
    UIActionSheet *popupQuery = [[UIActionSheet alloc] initWithTitle:nil delegate:self cancelButtonTitle:@"Cancel" destructiveButtonTitle:@"Edit" otherButtonTitles:@"Remove", @"Sell",@"Scrap", nil]; 
    popupQuery.actionSheetStyle = UIActionSheetStyleBlackTranslucent; 
    [popupQuery showInView:self.view]; 
    [popupQuery release]; 
} 
if (indexPath.row == 1) 
{ 
    UIActionSheet *popupQuery = [[UIActionSheet alloc] initWithTitle:nil delegate:self cancelButtonTitle:@"Cancel" destructiveButtonTitle:@"Unsell" otherButtonTitles:@"Edit Item", @"Edit Sale",@"Sold",@"Scrap", nil]; 
    popupQuery.tag=5; 
    popupQuery.actionSheetStyle = UIActionSheetStyleBlackOpaque; 
    [popupQuery showInView:self.view]; 
    [popupQuery release]; 
} 
} 

-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex { 
if (buttonIndex == 0) 
{ 
    Updateasset *object=[[Updateasset alloc]initWithNibName:@"Updateasset" bundle:nil]; 
    [self presentModalViewController:object animated:NO]; 
    [object release]; 
} 
else if (buttonIndex == 1) 
{ 
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Remove" message:@"Do you want to Remove" 
                delegate:self cancelButtonTitle:@"No" otherButtonTitles:@"Yes", nil]; 
    [alert show]; 
    [alert release]; 
} 
else if (buttonIndex == 2) 
{ 
    Egarageselling *object=[[Egarageselling alloc]initWithNibName:@"Egarageselling" bundle:nil]; 
    [self presentModalViewController:object animated:YES]; 
    [object release]; 
} 
else if (buttonIndex == 3) 
{ 
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Scrap" message:@"Do you want to Scrap" 
                delegate:self cancelButtonTitle:@"No" otherButtonTitles:@"Yes", nil]; 
    [alert show]; 
    [alert release]; 
} 
else if (buttonIndex == 4) 
{ 

} 
else if (buttonIndex == 5) 
{ 

} 
else if (buttonIndex == 6) 
{ 
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Scrap" message:@"Do you want to Scrap" 
                delegate:self cancelButtonTitle:@"No" otherButtonTitles:@"Yes", nil]; 
    [alert show]; 
    [alert release]; 
} 
else if (buttonIndex == 7) 
{ 
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Scrap" message:@"Do you want to Scrap" 
                delegate:self cancelButtonTitle:@"No" otherButtonTitles:@"Yes", nil]; 
    [alert show]; 
    [alert release]; 
} 
else if (buttonIndex == 8) 
{ 
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Scrap" message:@"Do you want to Scrap" 
                delegate:self cancelButtonTitle:@"No" otherButtonTitles:@"Yes", nil]; 
    [alert show]; 
    [alert release]; 
} 
else if (buttonIndex == 9) 
{ 
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Scrap" message:@"Do you want to Scrap" 
                delegate:self cancelButtonTitle:@"No" otherButtonTitles:@"Yes", nil]; 
    [alert show]; 
    [alert release]; 
} 
} 

如何解決這個問題。

Answer 1

爲兩個動作表設置不同的標籤，如 popupQuery.tag = 5; popupQuery.tag = 6;

-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex 
{ 
    if(actionSheet.tag==5) 
    { 
     if (buttonIndex == 0) 
     { 
     } 
     so on 
    } 
    if(actionSheet.tag==6) 
    { 
     if (buttonIndex == 0) 
     { 
     } 
     so on 
    } 

} 

Answer 2

我可能會補充一點，在這種情況下，我會說最好的做法是將您的操作表設置爲公共或私有實例變量。它看起來像這樣在你的頭文件（公共）：

@property (nonatomic, retain) UIActionSheet *as1; 
@property (nonatomic, retain) UIActionSheet *as2; 

在實現文件中你合成它們，就像這樣：

@synthesize as1, as2; 

然後記得從那裏你現在分配設置它們的popupQuery的今天：

... 
self.as1 = popupQuery; 
... 

... 
self.as2 = popupQuery; 
... 

而在你的委託方法你現在可以做這樣的（這也是我覺得更具可讀性，如果我要永遠存在另一個開發代碼）：

-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex 
{ 
    if(self.as1 == actionSheet) { 
     if (buttonIndex == 0) { ... } 
     ... 
    } 

    if(self.as2 == actionSheet) { 
     if (buttonIndex == 0) { ... } 
     ... 
    } 
} 

我希望你覺得它在這個和許多其他情況下很有用。我自己，一直這樣做。無論是公開還是私人蔘考，都不會對您造成任何損害。你永遠不知道他們什麼時候可以派上用場。