查找數組中最小值的索引號

Question

我必須返回12個數字數組中最小值的索引號。我每次運行它時都會得到12個結果。這裏是我的代碼：

minRain = leastRain(months); 

public static int leastRain (double[] mon4){ 
    int lowest = (int) mon4[0]; 

    for (int index=1; index<mon4.length; index++){ 
     if (mon4[index]<lowest) 
      lowest = index; 
    } 
    return lowest; 
} 

System.out.println("The month with the lowest amount of rain is: " + (minRain + 1)); 

Answer 1

您需要存儲lowest_seen和lowest_index。現在你正在比較價值< last_index

Answer 2

這是一個愚蠢的錯誤，你做了 - 你指定的變量，而不是一個數組值。這樣做：

public static int leastRain (double[] mon4){ 
    int lowest = 0; 

    for (int index=1; index<mon4.length; index++){ 
     if (mon4[index]<mon4[lowest]) 
      lowest = index; 
    } 
    return lowest; 
} 

Answer 3

這條語句的含義是什麼？

int lowest = (int) mon4[0]; 

您將數組的第一個值保存爲最低值，然後再與數組值進行比較。您實際上是將索引與數組值進行比較。

if (mon4[index]<lowest) // comparing lowest as an array value 
    lowest = index;  // saving the index as the lowest value 

你應該這樣做。

if (mon4[index]<mon4[lowest]) // comparing value of 'index' 'vs. 'lowest' index location 
    lowest = index; 

Answer 4

要指定數組值的lowest，所以改變它，如下圖所示：

public static int leastRain (double[] mon4){ 
    int lowestIndex = 0;//set index as 0 instead of array value 
    int lowestValue = mon4[0]; 
    for (int index=1; index<mon4.length; index++){ 
     if (mon4[index] < lowestValue) 
      lowestIndex = index; 
    } 
    return lowestIndex; 
}