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我已經安裝了WAMP並在本地主機上運行PHP腳本。我已啓用cURL。這是我的代碼。示例twitter應用程序
<?php
function updateTwitter($status)
{
// Twitter login information
$username = 'xxxxx';
$password = 'xxxxx';
// The url of the update function
$url = 'http://twitter.com/statuses/update.xml';
// Arguments we are posting to Twitter
$postargs = 'status='.urlencode($status);
// Will store the response we get from Twitter
$responseInfo=array();
// Initialize CURL
$ch = curl_init($url);
// Tell CURL we are doing a POST
curl_setopt($ch, CURLOPT_PROXY,"localhost:80");
curl_setopt ($ch, CURLOPT_POST, true);
// Give CURL the arguments in the POST
curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs);
// Set the username and password in the CURL call
curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password);
// Set some cur flags (not too important)
curl_setopt($ch, CURLOPT_VERBOSE, 1);
curl_setopt($ch, CURLOPT_NOBODY, 0);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
// execute the CURL call
$response = curl_exec($ch);
if($response === false)
{
echo 'Curl error: ' . curl_error($ch);
}
else
{
echo 'Operation completed without any errors<br/>';
}
// Get information about the response
$responseInfo=curl_getinfo($ch);
// Close the CURL connection curl_close($ch);
// Make sure we received a response from Twitter
if(intval($responseInfo['http_code'])==200){
// Display the response from Twitter
echo $response;
}else{
// Something went wrong
echo "Error: " . $responseInfo['http_code'];
}
curl_close($ch);
}
updateTwitter("Just finished a sweet tutorial on http://brandontreb.com");
?>
這裏是我的輸出
Operation completed without any errors
Error: 404
下面是錯誤404意味着
404未找到：這個URI請求無效或請求的資源，如用戶不存在。
請幫忙。