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我是新來的PHP在這裏，努力解決問題。我創建了一個表單將信息提交給後端的powershell腳本。我有一個下拉字段（電話），這是從MySQL拉動和填充。這部分工作很好。我遇到的問題是，當我發佈數據並將其傳遞給powershell腳本時，字段（電話）將作爲空白傳遞。我不確定我在哪裏可能導致問題，並在此尋找幫助。下拉選項填充MySQL選擇不張貼
這是我的。如果可能，我想保留在PHP中。
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
</head>
<body>
<?php
// If there was no submit variable passed to the script (i.e. user has visited the page without clicking submit), display the form:
if(!isset($_POST["submit"]))
{
?>
<form name="testForm" id="testForm" action="BTAM2.php" method="post" /> <br />
First Name: <input type="text" name="SAMname" id="SAMname" maxlength="20" /><br /> <br/>
Telephone Number:
<?php
$con=mysqli_connect("localhost","root","","it");
//============== check connection
if(mysqli_errno($con))
{
echo "Can't Connect to mySQL:".mysqli_connect_error();
}
//This creates the drop down box
echo "<select name='phonenum' id='phonenum'>";
echo '<option value="0">'.' '.'</option>';
$query = mysqli_query($con,"Select `btphonenumber` from `btphone` where `btuser` = ' '");
$query_display = mysqli_query($con,"SELECT * FROM btphone");
while($row=mysqli_fetch_array($query))
{
echo "<option value='". $row['id']."'>".$row['btphonenumber']
'';
}
echo '</select>';
?><br /> <br />
<input type="submit" name="submit" id="submit" value="Create User" />
</form>
<?php
}
// Else if submit was pressed, check if all of the required variables have a value:
elseif((isset($_POST["submit"])) && (!empty($_POST["SAMname"])))
{
// Get the variables submitted by POST in order to pass them to the PowerShell script:
$firstname = $_POST["SAMname"];
$telenumber = $_POST["phonenum"];
var_dump($_REQUEST);
}
// Else the user hit submit without all required fields being filled out:
其他 { 回聲「對不起，您沒有完成所有必填字段請返回重試。」; } ？>
你的名字= 'PHONENUM' 之間的空間。如果你刪除它會發生什麼？ – chepe263
@ chepe263 html標籤中的空白是無關緊要的。嘗試在'elseif'塊中執行'var_dump（$ _ POST）'並查看是否發佈到頁面的變量。同樣從'
' – elitechief21關閉。檢查輸出的html並確保電話'選項'標籤的值屬性選擇'正在填充您從數據庫中獲得的ID – elitechief21