Java JCombobox和JButton問題

Question

我目前正在爲我的計算機科學課程開展一個項目，並且遇到問題。我有多個按鈕和2個組合框，我希望它們全都獨立工作。不幸的是，每當我按下一個按鈕時，它就像一個「選擇」按鈕，並激活當前在組合框中選擇的任何東西！我將如何解決這個問題？我的代碼片段低於

public void actionPerformed(ActionEvent e) { 
    // Sound Menu 
    String soundSelect = (String)soundBox.getSelectedItem(); 
    int soundIndex = soundBox.getSelectedIndex(); 
    switch (soundIndex){ 
     case 0: 
     stopClip(meowSong); 
     stopClip(meowRemix); 
     ImageIcon catDel = new ImageIcon(getClass().getResource("tres-quatro.png")); 
     delEvent.setIcon(catDel); 
     ImageIcon catAdd = new ImageIcon(getClass().getResource("im-hungry.png")); 
     addEvent.setIcon(catAdd); 
     break; 
     case 1: 
     stopClip(meowRemix); 
     playMeow(meowSong); 
     catDel = new ImageIcon(getClass().getResource("tres-quatro.png")); 
     delEvent.setIcon(catDel); 
     catAdd = new ImageIcon(getClass().getResource("im-hungry.png")); 
     addEvent.setIcon(catAdd); 
     break; 
     case 2: 
     stopClip(meowSong); 
     playMeow(meowRemix); 
     ImageIcon thugCat = new ImageIcon(getClass().getResource("tres-quatro-thug.png")); 
     delEvent.setIcon(thugCat); 
     ImageIcon hungryThug = new ImageIcon(getClass().getResource("im-hungry-thug.png")); 
     addEvent.setIcon(hungryThug); 
     break; 
    } 


    // View Menu 
    String viewSelect = (String)viewTypes.getSelectedItem(); 
    if(e.getActionCommand().equals("ADD EVENT")) 
    { 
     playMeow(meowSound); 
     createEvent(); 
     }else if(e.getActionCommand().equals("DELETE EVENT")) 
     { 
      playMeow(meowSound); 
      deleteEvent(); 
     }else{ 
      panel.remove(displayMessage2); 
      panel.add(displayMessage); 
      panel.remove(text); 
     } 

    int selection = viewTypes.getSelectedIndex(); 
     switch (selection) 
     { 
      case 0: displayMessage.setText("Enter the Sunday of the week you'd like to view! DD/MM"); 
        panel.add(text); 
        panel.add(enter); 
        String date = text.getText(); 
        if(e.getActionCommand().equals("Enter")){ 
        weeklyCalendar(calendar.getHashmap(), date); 
        displayMessage.setText("Select a CATlendar view or you can ADD or DELETE an event!"); 
        panel.remove(text); 
        panel.remove(enter); 
        } 
        break; 
      case 1: displayMessage.setText("Enter the date you'd like to view! DD/MM"); 
        panel.add(text); 
        panel.add(enter); 
        date = text.getText(); 
        if(e.getActionCommand().equals("Enter")){ 
        playMeow(meowSound); 
        dailyCalendar(calendar.getHashmap(), date); 
        displayMessage.setText("Select a CATlendar view or you can ADD or DELETE an event!"); 
        panel.remove(text); 
        panel.remove(enter); 
        } 
        break; 
     case 2: displayMessage.setText("Press Enter to view monthly"); 
       panel.remove(text); 
       panel.add(enter); 
       if(e.getActionCommand().equals("Enter")){ 
        monthlyCalendar(); 
        displayMessage.setText("Select a CATlendar view or you can ADD or DELETE an event!"); 
        panel.remove(enter); 
       } 
       break; 
      } 

    panel.revalidate(); 
    panel.repaint(); 
    SwingUtilities.windowForComponent(panel).pack(); 
} 

Answer 1

每當我按下一個按鈕，它可以作爲一個「選擇」按鈕，激活無論是目前在組合框中

那麼這就是你選擇的ActionListener代碼呢。無論生成ActionEvent的哪個組件，都始終執行switch語句。

爲每個組件創建單獨的ActionListeners，而不是嘗試共享所有組件的單個ActionListener。然後，代碼將針對每個組件特定，並且不需要if語句來確定哪個組件生成事件。

編輯：

你怎麼能爲每個組件單獨的ActionListeners？

1. 您可以創建一個實現ActionListener接口

   comboBox.addActionListener(new MyComboBoxListener()); 
   
   ... 
   
   class MyComboBoxListener implements ActionListener 
   { 
       @Override 
       public void actionPerformed(ActionEvent e) 
       { 
        // add your code here 
       } 
   } 
   

2. 您可以使用annonymous內部類

   comboBox.addActionListenener(new ActionListener() 
   { 
       @Override 
       public void actionPerformed(ActionEvent e) 
       { 
        // add your code here 
       } 
   });