分發數字範圍的各線程之間

Question

配置文件

ThreadSize = 10 
StartRange = 1 
EndRange = 1000 

我有一個配置文件以上，其中我有線程數我想使用與客戶端實例是能夠使用ID範圍從1至1000並且假設客戶端線程被設置爲10，所以每個線程的範圍可以是100個id（基本上通過將結束範圍除以線程大小），它可以使用而不用跨過其他線程。所以我想是每個線程應使用100點的ID從範圍，而不對其他threads-步進例如

Thread1 will use 1 to 100 (id's) 
// generate a random number between 1 to 100 and keep on printing values until it has generated all the random values between 1 to 100 
Thread2 will use 101 to 200 (id's) 
// generate a random number between 101 to 200 and keep on printing values until it has generated all the random values between 101 to 200 
Thread3 will use 201 to 300 (id's) 
// generate a random number between 201 to 300 and keep on printing values until it has generated all the random values between 201 to 300 

----- 
---- 
Thread10 will use 901 to 1000 
// generate a random number between 901 to 1000 and keep on printing values until it has generated all the random values between 901 to 1000 

我知道如何編寫多線程程序，但不知道我應該如何劃分不同的範圍線程。

public static void main(String[] args) { 

    for (int i = 1; i <= threadSize; i++) { 
     new Thread(new ThreadTask(i)).start(); 
    } 
} 


class ThreadTask implements Runnable { 
    private int id; 

    public ThreadTask(int id) { 
    this.id = id; 
    } 

    public synchronized void run() { 

    } 
} 

Answer 1

每個線程獲取N = (EndRange - StartRange + 1)/ThreadSize數字。

主題編號i獲取範圍(StartRange + i*N) - (StartRange + i*N + N - 1)。

在你的例子N = (1000 - 1 + 1)/10 = 100。

主題i = 0將得到範圍(1 + 0*100) - (1 + 0*100 + 100 - 1) = 1 - 100

主題i = 1將得到範圍(1 + 1*100) - (1 + 1*100 + 100 - 1) = 101 - 200

...