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我有一個從mysql表中提取數據並將其轉換爲pdf文檔的代碼,代碼工作正常,除了跳過第1行。mysql_fetch_array沒有獲取完整的數據?
這是我從中刪除pdf生成過程的代碼問題在於獲取數據的循環中。
請幫忙。
<?php
session_start();
if(isset($_SESSION['user']))
{
$cr = $_POST['cour'];
$s = $_POST['sem'];
require('fpdf.php');
include('../includes/connection.php');
$sql = "SELECT * FROM `student` WHERE AppliedCourse ='$cr'";
$rs = mysql_query($sql) or die($sql. "<br/>".mysql_error());
if(!mysql_fetch_array($rs))
{
$_SESSION['db_error'] = "<h2><font color = 'RED'>No such course found! Pease select again.</font></h2>";
header('Location: prinrepo.php');
}
else {
for($i = 0;$i <= $row = mysql_fetch_array($rs);$i++)
{
$formno[$i] = $row ['FormNo'];
$rno[$i] = $row ['rollno'];
$snm[$i] = $row ['StudentNm'];
$fnm[$i] = $row ['FathersNm'];
$mnm[$i] = $row ['MothersNm'];
$addr[$i] = $row['Address'];
$pic[$i] = $row['imagenm'];
$comm[$i] = $row['SocialCat'];
echo $formno[$i]."<br />";
echo $rno[$i]."<br />";
echo $snm[$i]."<br />";
echo $fnm[$i]."<br />";
echo $mnm[$i]."<br />";
echo $addr[$i]."<br />";
echo $pic[$i]."<br />";
echo $comm[$i]."<br />";
echo "<br />";
}
}
mysql_close($con);
}
?>
太感謝你了......它的工作 – Ash