while循環的輪數在遊戲中

我試圖創建一個簡單的while循環，它會在「分數」達到一定數量後停止。while循環的輪數在遊戲中

我能夠使它低於在工作的時候設置「發」的3個數字：

var_1 = 0 
var_2 = 0 

while var_1 < 3 and var_2 < 3: 
    choice = raw_input("Choose apple or orange.") 
    if choice.lower() == 'a' or choice.lower() == 'apple': 
     var_1 += 1 
     print "You like apples, huh?" 
     print "Apples: " + str(var_1) + "; Oranges: " + str(var_2) 
    elif choice.lower() == 'o' or choice.lower() == 'orange': 
     var_2 += 1 
     print "You like oranges, huh?" 
     print "Apples: " + str(var_1) + "; Oranges: " + str(var_2) 

print "Game over." 
if var_1 == 3: 
    print "Apples are more popular." 
elif var_2 == 3: 
    print "Oranges are more popular."

但....如果我有一個線的raw_input的代碼round_number讓播放器確定回合數，然後將該條件設置爲該變量，則不起作用：

var_1 = 0 
var_2 = 0 
round_number = raw_input("How many rounds would you like to play?") 
while var_1 < round_number and var_2 < round_number: 
    choice = raw_input("Choose apple or orange.") 
    if choice.lower() == 'a' or choice.lower() == 'apple': 
     var_1 += 1 
     print "You like apples, huh?" 
     print "Apples: " + str(var_1) + "; Oranges: " + str(var_2) 
    elif choice.lower() == 'o' or choice.lower() == 'orange': 
     var_2 += 1 
     print "You like oranges, huh?" 
     print "Apples: " + str(var_1) + "; Oranges: " + str(var_2) 

print "Game over." 
if var_1 == round_number: 
    print "Apples are more popular." 
elif var_2 == round_number: 
    print "Oranges are more popular."

我在做什麼錯？

來源

2013-11-04 user2953512

您需要將其轉換爲int。用int（）包裝raw_input函數調用：

round_number = int(raw_input("How many rounds would you like to play?"))

來源

2013-11-04 17:48:13 sheba

while循環的輪數在遊戲中

回答

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