我在這個遊戲中有衝突的代碼

Question

我一直在修改骰子游戲豬的代碼。我將它修改爲滾動2個骰子而不是1個骰子的位置。當你擲出一個時，它會轉向下一個玩家，並且你的分數與你之前的分數沒有任何差異。那麼當你滾動兩個我需要它將分數重置爲0並打印出我的消息「蛇眼！你的分數設置爲0」。問題是兩條消息都會打印出蛇眼，並且當你滾動一個滾動條時滾動一條。此外，分數不會重置。

編輯*我已經固定的代碼與衝突的打印消息，但仍然遇到麻煩分數時snakeyes被卷

from random import randint 

playercount = 2 
maxscore = 100 
safescore = [0] * playercount 
player = 0 
score=0 

while max(safescore) < maxscore: 
    if player == 0: 
     rolling = 0 
     if score < 17 and score + safescore[player] < maxscore: 
      rolling = 1 
    else: 
     rolling = input("Player %i: (%i, %i) Rolling? (Y) " 
      % (player, safescore[player], score)).strip().lower() in {'yes', 'y', ''} 
    if rolling: 
     rolled = randint(1, 6) 
     rolled2 = randint(1, 6) 
     print(' Rolled %i' % rolled) 
     print(' Rolled %i' % rolled2) 
     if rolled ==1 and rolled2 ==1: 
       print(' Snake Eyes!! your score is set to 0') 
       score=0 

     elif rolled == 1: 
      print(' Bust! you lose %i but still keep your previous %i' 
        % (score, safescore[player])) 
      score, player = 0, (player + 1) % playercount 
     elif rolled2 == 1: 
      print(' Bust! you lose %i but still keep your previous %i' 
        % (score, safescore[player])) 
      score, player = 0, (player + 1) % playercount 


     else: 
      score += rolled + rolled2 
    else: 
     safescore[player] += score 
     if safescore[player] >= maxscore: 
      break 
     print(' Sticking with %i' % safescore[player]) 
     score, player = 0, (player + 1) % playercount 

print('\nPlayer %i wins with a score of %i' %(player, safescore[player])) 

Answer 1

您需要糾正檢查的順序重置爲0。現在你的「滾動一個」檢查出現在「滾動兩個」檢查之前，所以它將在兩個滾動時執行。如果你把「兩個一」先檢查，使兩個獨家與其他-if結構，你會得到的行爲，你想：

if rolled==1 and rolled2==1: 
    # snake eyes 
elif rolled==1: 
    # a single one 
else: 
    # all other cases 

另外請注意，如果兩個骰子來到你目前只檢查或者如果第一次死亡來了一個。你可能還想檢查第二個死亡是否出現了。