2017-02-09 52 views
0

因此,我正在使用bing地圖v8編寫一個應用程序。不幸的是,它沒有z-index支持(儘管有z-index函數...)。所以我正在嘗試使用圖層來完成類似的事情。問題是當我在層之間交換引腳時,事件開始在正確的引腳位置上觸發錯誤的元數據。Bing地圖v8事件傳遞不正確的引腳?

這裏是我創建的引腳

function createImagePin(location, index, objArray) 
{ 
    var obj = objArray[index]; 
    var smallPin = getSmallPin(obj); 

    var pin = new Microsoft.Maps.Pushpin(location, 
    { 
     visible: true, 
     icon: smallPin.data, 
     anchor: new Microsoft.Maps.Point(smallPin.width/2, smallPin.height/2) //Align center of pushpin with location. 
    }); 

    pin.metadata = {}; 
    pin.metadata.index = index; 
    pin.metadata.dataTarget = obj; 
    pin.metadata.isSelected = false; 

    Microsoft.Maps.Events.addHandler(pin, 'click', function (e) { 

     if(e.targetType === 'pushpin') 
     { 
      SetRowSelection(e.target.metadata.index); 
     } 
    }); 

    Microsoft.Maps.Events.addHandler(pin, 'mouseover', function (e) 
    { 
     if(e.targetType === 'pushpin') 
     { 
      SelectPin(e.target); 
      ShowInfobox(e.target); 
      console.log(e.target.getLocation()); 
     } 
    }); 

    Microsoft.Maps.Events.addHandler(pin, 'mouseout', function (e) 
    { 
     if (e.targetType === 'pushpin') 
     { 
      DeselectPin(e.target); 
      HideInfobox(); 
     } 
    }); 

    return pin; 
} 

出於某種原因,我把每一個具有正確的位置,但不正確的元數據時得到一個腳物件在鼠標懸停。如果我評論取消選擇...我得到正確的兩個。

這是我如何選擇和取消選擇引腳。基於我給出的例子Bing Maps pushpin icon issues

還有沒有其他代碼觸摸這些引腳的時刻......這似乎很奇怪我。它幾乎就像內部它只是複製圖層中的一些信息,而不是移動附加到對象的所有項目。事實上,如果我只是註釋掉添加/刪除它會阻止向我傳遞不正確的數據......儘管我失去了Z-indexing。

function SelectPin(pin) 
{ 
    switch (pin.metadata.dataTarget.ComparableType) 
    { 
     case "Subject": 
      mapLayers.subjectLayer.remove(pin); 
      pin.setOptions({ visible: true, icon: largeGreenHouse.data, anchor: new Microsoft.Maps.Point(largeGreenHouse.width/2, largeGreenHouse.height/2) }); 
      break; 
     case "Listing Comp": 
      mapLayers.compLayer.remove(pin); 
      pin.setOptions({ visible: true, icon: largeBlueHouse.data, anchor: new Microsoft.Maps.Point(largeBlueHouse.width/2, largeBlueHouse.height/2) }); 
      break; 
     case "Sales Comp": 
      mapLayers.compLayer.remove(pin); 
      pin.setOptions({ visible: true, icon: largeBlueHouse.data, anchor: new Microsoft.Maps.Point(largeBlueHouse.width/2, largeBlueHouse.height/2) }); 
      break; 
     case "Hidden": 
      pin.setOptions({ visible: false }); 
      return; 
     default: 
      mapLayers.observableLayer.remove(pin); 
      pin.setOptions({ visible: true, icon: largeGreyHouse.data, anchor: new Microsoft.Maps.Point(largeGreyHouse.width/2, largeGreyHouse.height/2) }); 
      break; 
    } 

    mapLayers.selectionLayer.add(pin); 
    pin.metadata.isSelected = true; 
} 

function DeselectPin(pin) 
{ 
    if(!pin.metadata.isSelected) 
     return; 

    pin.metadata.isSelected = false; 
    mapLayers.selectionLayer.remove(pin); 
    switch (pin.metadata.dataTarget.ComparableType) 
    { 
     case "Subject": 
      pin.setOptions({ visible: true, icon: greenHouse.data, anchor: new Microsoft.Maps.Point(greenHouse.width/2, greenHouse.height/2) }); 
      mapLayers.subjectLayer.add(pin); 
      break; 
     case "Listing Comp": 
      pin.setOptions({ visible: true, icon: blueHouse.data, anchor: new Microsoft.Maps.Point(blueHouse.width/2, blueHouse.height/2) }); 
      mapLayers.compLayer.add(pin); 
      break; 
     case "Sales Comp": 
      pin.setOptions({ visible: true, icon: blueHouse.data, anchor: new Microsoft.Maps.Point(blueHouse.width/2, blueHouse.height/2) }); 
      mapLayers.compLayer.add(pin); 
      break; 
     case "Hidden": 
      pin.setOptions({ visible: false }); 
      return; 
     default: 
      pin.setOptions({ visible: true, icon: greyHouse.data, anchor: new Microsoft.Maps.Point(greyHouse.width/2, greyHouse.height/2) }); 
      mapLayers.observableLayer.add(pin); 
      break; 
    } 

回答

0

嗯,它似乎是一個數據問題而不是代碼問題。我的數據將被地理編碼爲相同的緯度/長度,用於某些不具有相同地址的屬性。因此,陣列的重新排列會導致不同的位置,同一個位置會獲得「頂部位置」。