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我正在執行以下代碼以從文本文件創建數據框。在創建數據框時面對「scala.MatchError:1201(類java.lang.Integer)」
import org.apache.spark.SparkContext
import org.apache.spark.SparkConf
import org.apache.spark.sql.{SQLContext, Row}
import org.apache.spark.sql.types.{StructType, StringType, StructField}
/**
* Created by PSwain on 6/19/2016.
*/
object RddToDataframe extends App {
val scnf=new SparkConf().setAppName("RddToDataFrame").setMaster("local[1]")
val sc = new SparkContext(scnf)
val sqlContext = new SQLContext(sc)
val employeeRdd=sc.textFile("C:\\Users\\pswain\\IdeaProjects\\test1\\src\\main\\resources\\employee")
//Creating schema
val employeeSchemaString="id name age"
val schema = StructType(employeeSchemaString.split(",").map(colNmae => StructField(colNmae,StringType,true)))
//Creating RowRdd
val rowRdd= employeeRdd.map(row => row.split(",")).map(row => Row(row(0).trim.toInt,row(1),row(2).trim.toInt))
//Creating dataframe = RDD[rowRdd] + schema
val employeeDF=sqlContext.createDataFrame(rowRdd,schema). registerTempTable("Employee")
sqlContext.sql("select * from Employee").show()
}
但是,當在InteliJ中執行時,我發現類型不匹配錯誤如下。無法確定爲什麼這個錯誤正在提交我只是將字符串轉換爲整數。員工文件具有以下輸入,它們全部顯示在一行中,但它們各自爲一行。
1201,薩蒂什南比亞,25 1202,克里希納,28 1203,amith,39 1204,JAVED,23 1205,prudvi,23
16/06/19 15:18:58 ERROR Executor: Exception in task 0.0 in stage 0.0 (TID 0)
scala.MatchError: 1201 (of class java.lang.Integer)
at org.apache.spark.sql.catalyst.CatalystTypeConverters$StringConverter$.toCatalystImpl(CatalystTypeConverters.scala:295)
at org.apache.spark.sql.catalyst.CatalystTypeConverters$StringConverter$.toCatalystImpl(CatalystTypeConverters.scala:294)
at org.apache.spark.sql.catalyst.CatalystTypeConverters$CatalystTypeConverter.toCatalyst(CatalystTypeConverters.scala:102)
你爲什麼要拆分'employeeSchemaString.split( 「 」)'和','如果字符串用空格'「 ID名年齡」'分開嗎? –