0
我創建了一個接收遠程推送規範的代碼，該代碼工作正常。現在我需要添加兩個「按鈕」，它們可以甩開並執行一個動作。我知道這下面的代碼是用來indetify動作遠程推送通知操作
func application(application: UIApplication, handleActionWithIdentifier identifier: String?, forLocalNotification notification: UILocalNotification, completionHandler:() -> Void) {
if identifier == "optin1" {
//do something
}
else identifier == "option2" {
//do something
}
completionHandler()
}
，但我不知道如何創建按鈕SWIP離開。我該怎麼辦呢
這是我的AppDelegate：
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool
{
// Override point for customization after application launch.
let types:UIUserNotificationType = [.Alert, .Sound, .Badge]
application.registerForRemoteNotifications()
application.registerUserNotificationSettings(UIUserNotificationSettings(forTypes: types, categories: nil))
initLocationManager()
return true
}
func application(application: UIApplication, didFailToRegisterForRemoteNotificationsWithError error: NSError) {
//print(error)
}
func application(application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: NSData) {
print(deviceToken)
}
func application(application: UIApplication, didReceiveRemoteNotificationuserInfo userInfo: [NSObject : AnyObject]) {
print(userInfo)
}