我掙扎了好幾個小時來理解和實現這個算法,我很確定,我按照標準算法做了所有事情,但仍然沒有工作。 我下面一個名爲書我的合併排序沒有給出正確的排序數組,任何人都可以解釋嗎?
#include<iostream>
using namespace std;
//function to divide the array until it has only one element
void merge_sort(int[], int, int);
// function to merge two sorted arrays
void merge(int[], int, int, int);
// global array - to write the final sorted array in this
int na[100];
void main() {
int a[50]; //input array
cout << "Enter an unsorted array of 10 elements" << endl;
for (int i = 0; i < 10; i++) {
cin >> a[i];
}
merge_sort(a, 0, 9); // calling merge_sort
for (int i = 0; i < 10; i++) {
//print final array
cout << na[i] << endl;
}
}
void merge_sort(int a[], int p, int r) {
// p is 0 , r is final bound
if (p < r) {
int q;
q = (p + r)/2; //finding middle element
merge_sort(a, p, q);
merge_sort(a, q + 1, r);
merge(a, p, q, r);
}
}
// for two sorted sub-array from p to q and from q+1 to r, this function
// will compare first element of each sub-array and will place the smaller
// one in final array until every element is sub-array is in final sorted
//array
void merge(int a[], int p, int q, int r) {
int n1 = q - p + 1;
int n2 = r - q;
int l[50];
int ri[50];
for (int i = 0; i < n1; i++) {
l[i] = a[p + i ];
}
l[n1] = 99999;
for (int j = 0; j < n1; j++) {
ri[j] = a[q + j + 1];
}
ri[n2] = 99999;
int i = 0;
int j = 0;
for (int k = p; k <= r; k++) {
if (l[i] <= ri[j]) {
na[k] = l[i];
i = i + 1;
}
else {
na[k] = ri[j];
j = j + 1;
}
}
}
你應該更新你的資源,'void main()'是不可接受的。 –
您可以檢查代碼和變量的行爲,逐行執行調試器。 – user0042
1)'j < n1;' -->'j
BLUEPIXY