多維數組 - mysql_fetch_assoc到JSON

我已經使用MySql _fetch_assoc然後json_encode多維數組 - mysql_fetch_assoc到JSON

$type = mysql_query("SELECT type_food,category_food,name_food FROM menu ORDER BY type_food,category_food,name_food"); 
    $rows = array(); 
    while($t = mysql_fetch_assoc($type)) { 
      $rows[]= $t;  
    } 
print json_encode($rows);

這給了我下面的結果：

{"type_food":"pizza","category_food":"Gourmet","name_food":"pepperoni"}, 
{"type_food":"pizza","category_food":"Gourmet","name_food":"supreme"}, 
{"type_food":"pizza","category_food":"Gourmet","name_food":"hawaiian"}, 
{"type_food":"pizza","category_food":"Gourmet","name_food":"tropical"}, 
{"type_food":"pizza","category_food":"traditional","name_food":"margherita"}, 
{"type_food":"pizza","category_food":"traditional","name_food":"vegetarian"}

但是我需要一個多維的JSON結果一樣所以：

{"pizza": [ 
    {"Gourmet": [ 
       {"pepperoni"}, 
       {"supreme"}, 
       {"hawaiian"}, 
       {"tropical"}]}, 
    {"traditional": [ 
       {"margherita"}, 
       {"vegetarian"}]} 
]}, 
{"etc": [ ... ]}

這是可能的使用MySQL關聯數組？

來源

2013-03-05 g r

你應該張貼的，你怎麼來了你的結果你的PHP代碼。 – kennypu 2013-03-05 04:21:57

更改你的mysql查詢。併發布一些代碼。 – 2013-03-05 04:25:15

你可以在你的mysql查詢中使用['GROUP_CONCAT（）']（http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat）（即''' GROUP_CONCAT（name_food）... GROUP by category_food'），然後'爆炸（'）'GROUP_CONCAT（name_food）'數組。 – Sean 2013-03-05 04:29:20

試試這個：

$type = mysql_query("SELECT type_food,category_food,name_food FROM menu ORDER BY type_food,category_food,name_food"); 
$rows = array(); 
while($t = mysql_fetch_array($type)) { 
$rows[$t['type_food']][$t['category_food']][]=$t['name_food']; 
} 
print json_encode($rows);

來源

2013-03-05 06:07:28 Kabir

這看起來非常好！謝謝你的幫助 – 2013-03-05 23:01:11

<?php 
$str='[{"type_food":"pizza", "category_food":"Gourmet", "name_food":"pepperoni"}, 
{"type_food":"pizza","category_food":"Gourmet","name_food":"supreme"}, 
{"type_food":"pizza","category_food":"Gourmet","name_food":"hawaiian"}, 
{"type_food":"pizza","category_food":"Gourmet","name_food":"tropical"}, 
{"type_food":"pizza","category_food":"traditional","name_food":"margherita"}, 
{"type_food":"pizza","category_food":"traditional","name_food":"vegetarian"}]'; 
$rows=json_decode($str,true); 
$res=array(); 
foreach($rows as $row) 
{ 
    $res[$row['type_food']][$row['category_food']][]=$row['name_food']; 
} 
echo json_encode($res); 
?>

來源

2013-03-05 04:41:15 realization

多維數組 - mysql_fetch_assoc到JSON

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