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有人可以看看我的代碼嗎?我正嘗試從上一頁的鏈接顯示記錄。當我回顯$ id(下面)時,它顯示前一頁中'id'的值。但是查詢返回表的所有行。我早點工作了。我從此改變了一些事情。請指出我在看什麼。先謝謝你。將超鏈接的值傳遞到新頁面
<?php
mysql_connect('host', 'userid', 'password') or die (mysql_error());
mysql_select_db('my_database') or die (mysql_error());
//$result = mysql_query("SELECT * from table");
$id= mysql_real_escape_string($_GET["id"]);
echo $id;
$result = mysql_query("SELECT * FROM uatbeta1 WHERE id=".intval($_REQUEST['id']));
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
$row = mysql_fetch_row($result);
echo $result;
while($row = mysql_fetch_array($result)){
//Display the results from the current row and a line break
echo "<table border='1'>";
echo "<tr>";
echo "<td>".$row['id']."</td>";
echo "<td>".$row['company']."</td>";
echo "<td>".$row['constructioncontractor']."</td>";
echo "<td>".$row['weldingcontractor']."</td>";
echo "<td>".$row['ndtcontractor']."</td>";
echo "<td>".$row['weldid']."</td>";
echo "<td>".$row['projectname']."</td>";
echo "<td>".$row['examinationdate']."</td>";
echo "<td>".$row['shift']."</td>";
echo "</tr>";
請不要使用mysql_功能,因爲它們被廢棄http://news.php.net/php.internals/53799 –
Klevis,你能推薦一個替代mysql_query? – user1937020
使用pdo http://php.net/manual/en/book.pdo.php或mysqli http://php.net/manual/en/mysqli.query.php –