我需要正則表達式來修改字符串

Question

有人可以幫我寫一個正則表達式來修改下面

mywebsite.com/images/products/12345678_pit.jpg<br> 
mywebsite.com/images/products/12345678_piat_a2.jpg 

的鏈接，鏈接：

mywebsite.com/images/zoomimage/12/12345678_var.jpg<br> 
mywebsite.com/images/zoomimage/12/12345678_var_a2.jpg 

我們看到

• products = zoomimage
• pit|piat = var
• 12345678 = 12/12345678（意味着第一2位/初始數）

由於

Answer 1

給你在PHP的示例，但是該正則表達式可以用另一種語言被重用：

$urls = array(
    'mywebsite.com/images/products/12345678_pit.jpg', 
    'mywebsite.com/images/products/23456789_foo.jpg', 
    'mywebsite.com/images/products/34567890_bar.jpg', 
    'mywebsite.com/images/products/12345678_piat_a2.jpg', 
    'mywebsite.com/images/products/45678901_baz_a2.jpg', 
    'mywebsite.com/images/products/56789012_qux_a2.jpg' 
); 
foreach($urls as $url) { 
    echo preg_replace(
     '/products\/(\d{2})(\d*)_[a-z-]+(.*)\.jpg/i', 
     'zoomimage/$1/$1$2_var$3.jpg', $url) .'<br>'; 
} 
// mywebsite.com/images/zoomimage/12/12345678_var.jpg 
// mywebsite.com/images/zoomimage/23/23456789_var.jpg 
// mywebsite.com/images/zoomimage/34/34567890_var.jpg 
// mywebsite.com/images/zoomimage/12/12345678_var_a2.jpg 
// mywebsite.com/images/zoomimage/45/45678901_var_a2.jpg 
// mywebsite.com/images/zoomimage/56/56789012_var_a2.jpg