我的代碼有問題..我試圖添加一個搜索功能到我的列表視圖在Android ..它是以某種方式工作,但是當我搜索它給了我其他活動不是真正的結果..喜歡在我的列表視圖,如果我搜索銷售即5日活動它顯示的結果,但是當我點擊打開活動打開它撒尼活性,即列表中的第一個活動...Android的Listview搜索功能
下面是活動的Java代碼
package com.example.bati;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.widget.SearchView;
import android.widget.SearchView.OnQueryTextListener;
public class MainActivity extends Activity {
ListView lv;
SearchView sv;
String[] teams = {"Sani", "Bali", "Sati", "Umam", "sale"};
ArrayAdapter<String> adapter;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
lv = (ListView) findViewById(R.id.listView1);
adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, teams);
lv.setAdapter(adapter);
sv.setOnQueryTextListener(new OnQueryTextListener() {
@Override
public boolean onQueryTextSubmit(String query) {
return false;
}
@Override
public boolean onQueryTextChange(String newText) {
adapter.getFilter().filter(newText);
return false;
}
});
lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
if (position == 0) {
Intent myIntent = new Intent(view.getContext(), Sani.class);
startActivityForResult(myIntent, 0);
}
if (position == 1) {
Intent myIntent = new Intent(view.getContext(), Bali.class);
startActivityForResult(myIntent, 1);
}
if (position == 2) {
Intent myIntent = new Intent(view.getContext(), Sati.class);
startActivityForResult(myIntent, 2);
}
}
});
}
}
謝謝兄弟,它的工作原理 – Elpedia
不客氣如果你接受和upvote我的答案會很高興。謝謝。 – savepopulation