0
我對這種情況感到困惑。有這兩個類別:Nhibernate:外鍵必須與引用的主鍵具有相同的列數
public class TxType {
public TxType()
{
Payments = new List<Payment>();
}
public string TxTypeId { get; set; }
public string TxCode { get; set; }
public IList<Payment> Payments { get; set; }
public string Description { get; set; } }
public class Payment {
public Payment() { }
public string Trn { get; set; }
public TxType TxTypeId { get; set; }
public string TxCode { get; set; }
public System.Nullable<decimal> Amount { get; set; }
public System.Nullable<System.DateTime> DateStamp { get; set; } }
TxType表有兩個PK(TxTypeId,TxCode),並且都在付款表中都是FK。 這是我的映射:
<class name="TxType" table="TxType" lazy="false" >
<composite-id>
<key-property name="TxTypeId" column="TxTypeId" />
<key-property name="TxCode" column="TxCode" />
</composite-id>
<property name="Description">
<column name="Description" sql-type="nvarchar" not-null="false" />
</property>
<bag name="Payments" inverse="true" cascade="none">
<key>
<column name="TxTypeId" />
<column name="TxCode" />
</key>
<one-to-many class="MyProject.Nhibernate.Repository.Payment" not-found="ignore" />
</bag>
</class>
<class name="Payment" table="Payment" lazy="false" >
<id name="Trn">
<generator class="identity" />
</id>
<many-to-one insert="false" update="false" lazy="false" name="TxTypeId">
<column name="TxTypeId" sql-type="varchar" not-null="false" />
</many-to-one>
<property name="TxTypeId">
<column name="TxTypeId" sql-type="varchar" not-null="false" />
</property>
<many-to-one insert="false" update="false" lazy="false" name="TxCode">
<column name="TxCode" sql-type="varchar" not-null="false" />
</many-to-one>
<property name="TxCode">
<column name="TxCode" sql-type="varchar" not-null="false" />
</property>
<property name="Amount">
<column name="Amount" sql-type="decimal" not-null="false" />
</property>
<property name="DateStamp">
<column name="DateStamp" sql-type="datetime" not-null="false" />
</property>
</class>
而且我堅持了這個錯誤: 外鍵(FKF4FA0208CDBA724F:付款[TxTypeId]))必須具有相同的號碼作爲參照的主鍵(TxType [TxTypeId列, TxCode])。
謝謝!
好吧,我想通了,通過增加支付映射這些行:
<many-to-one name="TxType" class="MyProject.Nhibernate.Repository.TxType" insert="false" update="false" lazy="false" >
<column name="TxTypeId" sql-type="varchar" not-null="false" />
<column name="TxCode" sql-type="varchar" not-null="false" />
</many-to-one>
謝謝!
不axactly一個問題的答案,但如果你設置'<包名稱=「付款」逆=「真」>'和'<多到一個名稱=「TxType」插入=「假「update =」false「>'您無法向交易添加任何付款 – Firo