如何找到特定的價值存在於JSON字符串

Question

在這裏，我有一個數組，在這個數組我還有一個叫陣列studentabsentId，這裏其實studentabsentId 1是2017年4月11日和2017-缺席04-12

echo $json = json_encode($optionsList); 

結果

[ 
    { 
    "studentabsentId": [ 
     "1", 
     "2" 
    ], 
    "studentAbsentDate": "2017-04-11" 
    }, 
    { 
    "studentabsentId": [ 
     "1" 
    ], 
    "studentAbsentDate": "2017-04-12" 
    }, 
    { 
    "studentabsentId": [ 
     "2" 
    ], 
    "studentAbsentDate": "2017-04-13" 
    } 
] 

studentabsentId 2缺席2017年4月11日和2017年4月13日，現在我想做的事是指ID 2這是迄今爲止不存在，

預期結果

{ 
    "status": "Success", 
    "data": [ 
    { 
     "studentAbsentId": "2" 
     "studentAbsentDate": "2017-04-11", 
     "response":"absent" 
    }, 

{ 
    "studentAbsentId": "2" 
    "studentAbsentDate": "2017-04-13", 
    "response":"absent" 
} 
] 
} 

我更新的代碼

$json = json_encode($optionsList); 
      $result = array(); 
       for($i = 0; $i<count($json); $i++){ 
        for($j = 0; $j<count($json[$i]->studentabsentId); $j++){ 
         if($json[$i]->studentabsentId[$j] === "2"){ 
          array_push($result, 
           (object)[ 
           "studentabsentId" => $json[$i]->studentabsentId[$j], 
           "studentAbsentDate" => $json[$i]->studentAbsentDate, 
           ]); 
         } 
        } 
       } 
       //echo(print_r($result)); 

       $expected_result = (object)[ 
        "status" => "Success", 
        "data" => $result 
       ]; 

       echo(print_r($expected_result)); 

Answer 1

PHP版本，沙箱http://sandbox.onlinephpfunctions.com/code/c7991f23dc9bdd304eb50e27a06b68495564fa94：

<?php 
$json = array(
(object) [ 
    "studentabsentId" => array("1", "2"), 
    "studentAbsentDate" => "2017-04-11" 
    ], 
    (object) [ 
    "studentabsentId" => array("1"), 
    "studentAbsentDate" => "2017-04-12" 
    ], 
    (object) [ 
    "studentabsentId" => array("2"), 
    "studentAbsentDate" => "2017-04-13" 
    ] 
); 
//echo(print_r($json)); 

$result = array(); 
for($i = 0; $i<count($json); $i++){ 
    for($j = 0; $j<count($json[$i]->studentabsentId); $j++){ 
     if($json[$i]->studentabsentId[$j] === "2"){ 
      array_push($result, 
       (object)[ 
       "studentabsentId" => $json[$i]->studentabsentId[$j], 
       "studentAbsentDate" => $json[$i]->studentAbsentDate, 
       ]); 
     } 
    } 
} 
//echo(print_r($result)); 

$expected_result = (object)[ 
    "status" => "Success", 
    "data" => $result 
]; 

echo(print_r($expected_result)); 
?> 

JS VERS離子jsfiddle https://jsfiddle.net/czdqqegq/

var json = [ 
    { 
    "studentabsentId": [ 
     "1", 
     "2" 
    ], 
    "studentAbsentDate": "2017-04-11" 
    }, 
    { 
    "studentabsentId": [ 
     "1" 
    ], 
    "studentAbsentDate": "2017-04-12" 
    }, 
    { 
    "studentabsentId": [ 
     "2" 
    ], 
    "studentAbsentDate": "2017-04-13" 
    } 
]; 
var result = []; 

for(var i = 0; i<json.length; i++){ 
    for(var j =0; j<json[i].studentabsentId.length; j++){ 
    if(json[i].studentabsentId[j] === "2"){ /*Filter out where ID is 2*/ 
     result.push({ 
      "studentAbsentId" : json[i].studentabsentId[j], 
      "studentAbsentDate" : json[i].studentAbsentDate  
     }); 
    } 
    } 
} 
var expected_results = { 
    "status" : "Success", 
    "data" : result 
} 
console.log(expected_results);