在FIND_IN_SET中使用MySQL IN條件

Question

我有一個查詢，我使用一個相當密集的WHERE IN子句來獲取與玩家相關的ID列表。

SELECT p.name, 
    0a.stat_value 
FROM leaderheadsplayers p 
LEFT JOIN leaderheadsplayersdata_alltime 0a 
ON 0a.player_id = p.player_id 
AND 0a.stat_type = 'kills' 
WHERE p.player_id IN 
    (SELECT player_id 
    FROM 
    (SELECT 0a.player_id 
    FROM leaderheadsplayersdata_alltime 0a 
    WHERE 0a.stat_type = 'kills' 
    ORDER BY 0a.stat_value DESC LIMIT 0, 
     20 
    ) 1a 
) 

的問題是，我想用FIND_IN_SET沒有再做從IN子句密集的查詢，以保持這些ID的從IN子句的順序在我的最終結果。 事情是這樣的：

SELECT p.name, 
    0a.stat_value 
FROM leaderheadsplayers p 
LEFT JOIN leaderheadsplayersdata_alltime 0a 
ON 0a.player_id = p.player_id 
AND 0a.stat_type = 'kills' 
WHERE p.player_id IN 
    (SELECT player_id 
    FROM 
    (SELECT 0a.player_id 
    FROM leaderheadsplayersdata_alltime 0a 
    WHERE 0a.stat_type = 'kills' 
    ORDER BY 0a.stat_value DESC LIMIT 0, 
     20 
    ) 1a 
) 
ORDER BY FIND_IN_SET(p.player_id, result_from_in_clause) 

這是我的電流輸出：

player_id | stat_value 
3 | 304 
5 | 507 
4 | 208 

這就是我想：

player_id | stat_value 
5 | 507 
3 | 304 
4 | 208 

Answer 1

簡單order by應該能夠能夠做到這一點：

SELECT p.name, 
    0a.stat_value 
FROM leaderheadsplayers p 
LEFT JOIN leaderheadsplayersdata_alltime 0a 
ON 0a.player_id = p.player_id 
AND 0a.stat_type = 'kills' 
WHERE p.player_id IN 
    (SELECT player_id 
    FROM 
    (SELECT 0a.player_id 
    FROM leaderheadsplayersdata_alltime 0a 
    WHERE 0a.stat_type = 'kills' 
    ORDER BY 0a.stat_value DESC LIMIT 0, 
     20 
    ) 1a 
) 
order by 
    0a.stat_value, p.player_id;