如何打印新行從一個bash函數內

Question

我有以下bash腳本文件內的一段代碼：

#! /bin/sh 
# 
# Usage: 
# 
# f.sh <start_directory> <destination_directory> <prepare_directory> <remote_host_for_copy> <remote_user> 
# 
print_correct_syntax() { 

echo "f.sh <start_directory> <destination_directory> <prepare_directory> <remote_host_for_copy> <remote_user>" 
echo "" 
echo '<start_directory> needs to be a full path, <destination_directory> needs to be full path, <prepare_directory> has to be relative to start_directory path' 
echo "" 

} 
# ---- end of function definition ---- 

# check number of run-time arguments given to script 

if [ $# != 5 ] 
then 
echo Wrong Syntax! $(print_correct_syntax) 
exit; 
fi 
#--------------------------------------------------- 

函數內的回波空字符串命令（回聲「」）（print_correct_syntax）似乎沒有工作。相反，相同的外部函數命令似乎工作正常。如何從bash函數內打印空白換行符？

Answer 1

您在反引號（或$()）中放入的內容將換行符轉換爲空格。您可以直接調用該函數，而不是在反引號內使用它。

換句話說，該函數實際上會生成空行，但當您在最終的echo中使用$()時，反向查詢過程會將它們轉換爲空格。

Answer 2

嘗試更換：

echo Wrong Syntax! $(print_correct_syntax) 

由：

echo Wrong Syntax! "$(print_correct_syntax)"