我正在寫代碼,它將接受來自arduino的字節值,將它們存儲爲數組,然後執行一些數學計算,然後將值發送回arduino。現在我可以向Arduino發送127個值,並返回127個值,但是它們是字符串類型,並且任何使用Integer類轉換這些字符串的嘗試都會導致程序掛起。我相信緩衝區有時會提供空字符串,而parseInt()不知道該怎麼做。有沒有人有什麼建議?我非常喜歡java的初學者,並且願意提供更好的解決方案。在Java中將輸入流轉換爲數組的最佳方式是什麼?
這裏是我的代碼:
package GridMap;
import gnu.io.CommPort;
import gnu.io.CommPortIdentifier;
import gnu.io.SerialPort;
import gnu.io.SerialPortEvent;
import gnu.io.SerialPortEventListener;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
/**
*
*/
public class SerialWriter implements Runnable {
OutputStream out;
byte array[] = new byte[10];
byte c;
public SerialWriter(OutputStream out, byte[] in) {
this.out = out;
array = in;
}
public void run() {
try {
int index = 0;
c = array[index];
while ((c) > -1) {
this.out.write(c);
System.out.println("sent " + c);
if (index == 64){
Thread.sleep(2);
}
index++;
c = array[index];
}
TwoWaySerialComm.recieve();
} catch (Exception e) {
e.printStackTrace();
System.exit(-1);
}
}
}
public class SerialReader implements Runnable {
static byte[] output = new byte[128];
private InputStream in;
private int[] buffer = new int[11];
static SerialPort thisSerialPort;
static OutputStream thisOut;
static String total = new String("333");
public SerialReader(InputStream in) {
this.in = in;
for (byte i = 0; i < 127; i++) {
output[i] = i;
}
output[127] = - 1;
}
public void run()
{
byte[] buffer = new byte[1024];
int len = -1;
int index = 0;
int value;
try
{
Thread.sleep(200);
while ((len = this.in.read(buffer)) > -1 && index < 200)
{
String string = new String(buffer, 0, len);
//value = Integer.getInteger(string, len);
// System.out.print(value);
//System.out.println("buffer" + value);
System.out.print(string);
index++;
}
TwoWaySerialComm.send(output);
}
catch (Exception e)
{
e.printStackTrace();
}
}
public static int byteArrayToInt(byte[] b)
{
return b[3] & 0xFF |
(b[2] & 0xFF) << 8 |
(b[1] & 0xFF) << 16 |
(b[0] & 0xFF) << 24;
}
}
public class TwoWaySerialComm {
static SerialPort serialPort;
static OutputStream out = null;
static InputStream in;
static Thread receiveThread;
static Thread sendThread;
static byte[] output = new byte[11];
public TwoWaySerialComm() {
super();
}
void connect(String portName) throws Exception {
CommPortIdentifier portIdentifier = CommPortIdentifier.getPortIdentifier(portName);
if (portIdentifier.isCurrentlyOwned()) {
System.out.println("Error: Port is currently in use");
} else {
CommPort commPort = portIdentifier.open(this.getClass().getName(), 2000);
if (commPort instanceof SerialPort) {
serialPort = (SerialPort) commPort;
serialPort.setSerialPortParams(114400, SerialPort.DATABITS_8, SerialPort.STOPBITS_1, SerialPort.PARITY_NONE);
} else {
System.out.println("Error: Only serial ports are handled by this example.");
}
}
}
static void send(byte[] output) {
try {
out = serialPort.getOutputStream();
sendThread = new Thread(new SerialWriter(out, output));
sendThread.start();
//sendThread.join();
} catch (Exception e) {
System.out.println("Port Not Avaialable (send) ");
}
}
static void recieve(){
try {
in = serialPort.getInputStream();
receiveThread = new Thread(new SerialReader(in));
receiveThread.start();
receiveThread.join();
} catch (Exception e) {
}
}
public static void main(String[] args) {
try {
(new TwoWaySerialComm()).connect("COM3");
for (byte i = 0; i < 10; i++) {
output[i] = i;
}
output[10] = -1;
send(output);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static SerialPort returnSerialPort(){
return serialPort;
}
}
對不起,有沒有什麼辦法可以讓你更清楚! – NINCOMPOOP 2013-04-21 17:49:50