哪些錯誤與這個MySQL功能

Question

我已經看到了這個功能，在這個環節上：

http://www.artfulsoftware.com/infotree/queries.php#552

CREATE FUNCTION levenshtein(s1 VARCHAR(255), s2 VARCHAR(255)) 
    RETURNS INT 
    DETERMINISTIC 
    BEGIN 
    DECLARE s1_len, s2_len, i, j, c, c_temp, cost INT; 
    DECLARE s1_char CHAR; 
    -- max strlen=255 
    DECLARE cv0, cv1 VARBINARY(256); 
    SET s1_len = CHAR_LENGTH(s1), s2_len = CHAR_LENGTH(s2), cv1 = 0x00, j = 1, i = 1, c = 0; 
    IF s1 = s2 THEN 
     RETURN 0; 
    ELSEIF s1_len = 0 THEN 
     RETURN s2_len; 
    ELSEIF s2_len = 0 THEN 
     RETURN s1_len; 
    ELSE 
     WHILE j <= s2_len DO 
     SET cv1 = CONCAT(cv1, UNHEX(HEX(j))), j = j + 1; 
     END WHILE; 
     WHILE i <= s1_len DO 
     SET s1_char = SUBSTRING(s1, i, 1), c = i, cv0 = UNHEX(HEX(i)), j = 1; 
     WHILE j <= s2_len DO 
      SET c = c + 1; 
      IF s1_char = SUBSTRING(s2, j, 1) THEN 
      SET cost = 0; ELSE SET cost = 1; 
      END IF; 
      SET c_temp = CONV(HEX(SUBSTRING(cv1, j, 1)), 16, 10) + cost; 
      IF c > c_temp THEN SET c = c_temp; END IF; 
      SET c_temp = CONV(HEX(SUBSTRING(cv1, j+1, 1)), 16, 10) + 1; 
      IF c > c_temp THEN 
       SET c = c_temp; 
      END IF; 
      SET cv0 = CONCAT(cv0, UNHEX(HEX(c))), j = j + 1; 
     END WHILE; 
     SET cv1 = cv0, i = i + 1; 
     END WHILE; 
    END IF; 
    RETURN c; 
    END; 

但是，當我嘗試執行我得到這個錯誤信息：

1064 - 你的SQL語法有錯誤;檢查對應於你的MySQL服務器版本5行

MySQL版本使用「」附近正確語法手冊：53年5月1日

Answer 1

分隔符！

DELIMITER $$ 

CREATE FUNCTION levenshtein(s1 VARCHAR(255), s2 VARCHAR(255)) 
    RETURNS INT 
    DETERMINISTIC 
    BEGIN 
    ... 
    ... 
    ... 
    END$$ 

DELIMITER ;