檢查對是否相等

Question

這應該是一個非常簡單的程序，但是無論何時我嘗試編譯它，我都會收到一個錯誤消息，指出找不到otherObject.fst和otherObject.snd變量，所以我的等號方法無法正常工作。其他一切工作正常。我相信這是我的setFst和setSnd方法的問題。我試過了一堆變體，但我似乎無法正確地說出它。任何幫助將非常感激！

public class Pair<T1, T2> implements PairInterface<T1, T2> 
{ 
    // TO DO: Instance Variables 
    public T1 first; 
    public T2 second; 
    public T1 fst; 
    public T2 snd; 

    public Pair(T1 aFirst, T2 aSecond) 
    { 
     first = aFirst; 
     second = aSecond; 
    } 

    /** 
    * Gets the first element of this pair. 
    * @return the first element of this pair. 
    */ 
    public T1 fst() 
    { 
     return this.first; 
    } 

    /** 
    * Gets the second element of this pair. 
    * @return the second element of this pair. 
    */ 
    public T2 snd() 
    { 
     return this.second; 
    } 

    /** 
    * Sets the first element to aFirst. 
    * @param aFirst the new first element 
    */ 
    public void setFst(T1 aFirst) 
    { 
     // TO DO 
     aFirst = fst; 
    } 

    /** 
    * Sets the second element to aSecond. 
    * @param aSecond the new second element 
    */ 
    public void setSnd(T2 aSecond) 
    { 
     // TO DO 
     aSecond = snd; 
    } 

    /** 
    * Checks whether two pairs are equal. Note that the pair 
    * (a,b) is equal to the pair (x,y) if and only if a is 
    * equal to x and b is equal to y. 
    * @return true if this pair is equal to aPair. Otherwise 
    * return false. 
    */ 
    public boolean equals(Object otherObject) 
    { 
     if (otherObject == null) 
     { 
      return false; 
     } 

     if (getClass() != otherObject.getClass()) 
     { 
      return false; 
     } 
     if (otherObject.fst.equals(this.fst) && otherObject.snd.equals(this.snd)) 
     { 
      return true; 
     } 
     else 
     { 
      return false; 
     } 
     // TO DO 
    } 

    /** 
    * Generates a string representing this pair. Note that 
    * the String representing the pair (x,y) is "(x,y)". There 
    * is no whitespace unless x or y or both contain whitespace 
    * themselves. 
    * @return a string representing this pair. 
    */ 
    public String toString() 
    { 
     // TO DO 
     return "("+first.toString()+","+second.toString()+")"; 
    } 
} 

Answer 1

otherObject被聲明爲只是一個Object類型，所以它沒有你創建的任何類的任何屬性。它應該與您試圖比較的對象類型相同。