我寫了一個用戶註冊服務,如果用戶已經存在,應該拋出異常。下面是寄存器方法的代碼:Java不拋出異常
public User register(User user, String role) throws UserExistsException{
boolean userExists = existUserInDB(user);
if(userExists) {
logger.info("Yes, this user exists!");
throw new UserExistsException("This user already exists in database!");
}
try {
String encryptedPassword = getEncryptedPassword(user.getPassword(), getSalt(user));
user.setPassword(encryptedPassword);
Role userRole;
if (role == null){
TypedQuery<Role> query = entityManager.createQuery(
"SELECT r "+
"FROM Role r "+
"WHERE rolename = 'User'", Role.class);
userRole = query.getSingleResult();
} else {
TypedQuery<Role> query = entityManager.createQuery(
"SELECT r "+
"FROM Role r "+
"WHERE rolename = '"+role+"'", Role.class);
userRole = query.getSingleResult();
}
user.getRoles().add(userRole);
userRole.getUsers().add(user);
entityManager.persist(userRole);
entityManager.persist(user);
} catch (NoSuchAlgorithmException | NoSuchProviderException e) {
logger.warning("CryptAPI faild: " + e.getMessage());
}
return user;
}
測井證實,該existUserInDB方法返回正確的布爾值。給定的用戶存在於數據庫中。但是這個例外從未拋出。 我在我的應用程序中有很多自我實現的異常,它們都被正確引發和捕獲。除了這一個之外。有人可以幫助我嗎?
這裏是我調用註冊方法的代碼。
public String register() {
regUser.setEmail(this.emailAdd);
try {
userService.register(regUser, userRole);
FacesContext context = FacesContext.getCurrentInstance();
context.addMessage(null, new FacesMessage(FacesMessage.SEVERITY_INFO,"Der Benutzer wurde erfolgreich registriert.", null));
context.getExternalContext().getFlash().setKeepMessages(true);
} catch (UserExistsException e) {
FacesContext.getCurrentInstance().addMessage(null, new FacesMessage(FacesMessage.SEVERITY_ERROR,"Der Benutzer ist bereits registriert!", null));
}
curSession.setCurrentUser(regUser);
init();
return "home.xhtml?faces-redirect=true";
}
這裏是異常的類定義:
public class UserExistsException extends Exception {
private static final long serialVersionUID = -9218609941894034576L;
public UserExistsException(){
super();
}
public UserExistsException(String message){
super(message);
}
}
哪個異常應該拋出?如果一切都是正確的,爲什麼它應該被拋出? – Thomas
是這行打印? 'logger.info(「是的,這個用戶存在!」);' – Azodious
然後,顯示你期待這個異常的代碼。即從哪裏調用register? – Azodious