我們有一箇舊網站,我已經實現了一個由AngularJS發送給PHP腳本並在處理完電子郵件後發送的表單。如果表單無效,PHP腳本將返回一個帶有驗證錯誤的JSON。由於我們已經在一些其他應用程序(REST API)中使用Symfony,所以我認爲在Symfony中重新實現我的普通PHP腳本會很好。Symfony2:通過AJAX手動提交沒有類的表單
爲了簡單起見,我只放了一小段但相關的代碼片段。這是我有:
<form name="infoscreenForm" class="form-horizontal" enctype="multipart/form-data" ng-controller="FormController">
<div class="form-group">
<div class="col-lg-1 control-label">*</div>
<div class="col-lg-11 input-group">
<input type="text" class="form-control" id="contact_person"
name="contact_person" ng-model="formData.contactPerson"
placeholder="Kontaktperson">
</div>
<span class="text-warning" ng-show="errors.contactPerson">
{{ errors.contactPerson }}
</span>
</div>
<div class="form-group">
<div class="col-lg-1 control-label">*</div>
<div class="col-lg-11 input-group">
<span class="input-group-addon">@</span>
<input type="email" class="form-control" id="email" name="email"
ng-model="formData.email" placeholder="E-Mail">
</div>
<span class="text-warning" ng-show="errors.email">
{{ errors.email }}
</span>
</div>
<div class="form-group">
<div class="col-lg-1 control-label"> </div>
<div class="col-lg-11 input-group">
<input type="file" class="form-control" id="file" name="file"
file-model="formData.file"
accept="application/pdf,image/jpeg,image/png">
</div>
<span class="text-warning" ng-show="errors.file">
{{ errors.file }}
</span>
</div>
<div class="form-group">
<button type="submit" class="btn btn-default" id="submit"
name="submit" ng-click="submitForm()">
Formular absenden
</button>
</div>
</form>
JS:
HTML(NG-應用程序是在body標籤,這裏沒有顯示約束)
var app = angular.module('InfoscreenApp', []);
app.directive('fileModel', ['$parse', function ($parse) {
return {
restrict: 'A',
link: function (scope, element, attrs) {
var model = $parse(attrs.fileModel);
var modelSetter = model.assign;
element.bind('change', function() {
scope.$apply(function() {
modelSetter(scope, element[0].files[0]);
});
});
}
};
}]);
app.factory('multipartForm', ['$http', function ($http) {
return {
post : function (uploadUrl, data) {
var fd = new FormData();
for (var key in data) {
fd.append(key, data[key]);
}
return $http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers : { 'Content-Type': undefined }
});
}
};
}]);
app.controller('FormController', ['$scope', 'multipartForm', function ($scope, multipartForm) {
$scope.formData = {};
$scope.submitForm = function() {
var uploadUrl = 'http://localhost:8000/infoscreen';
multipartForm.post(uploadUrl, $scope.formData)
.then(function (data) {
console.log(data);
if (data.success) {
$scope.message = data.data.message;
console.log(data.data.message);
} else {
$scope.errors = data.data.errors;
}
});
};
}]);
全部用純PHP腳本一切工作正常。以下是我試過的Symfony做:
<?php
namespace AppBundle\Controller;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Form\Extension\Core\Type\TextType;
use Symfony\Component\Form\Extension\Core\Type\EmailType;
use Symfony\Component\Form\Extension\Core\Type\FileType;
use Symfony\Component\Form\Extension\Core\Type\SubmitType;
use Symfony\Component\Validator\Constraints\NotBlank;
use Symfony\Component\Validator\Constraints\Email;
class DefaultController extends Controller
{
/**
* @Route("/infoscreen", name="infoscreen")
*/
public function infoscreenAction(Request $request)
{
$defaultData = array('message' => 'infoscreenForm');
$form = $this->createFormBuilder($defaultData)
->add('contactPerson', TextType::class, array(
'constraints' => array(
new NotBlank(),
)
))
->add('email', EmailType::class, array(
'constraints' => array(
new NotBlank(),
new Email(),
)
))
->add('file', FileType::class)
->add('submit', SubmitType::class)
->getForm();
;
$form->submit($request->request->get($form->getName()));
$data = $form->getData();
if ($form->isValid()) {
echo 'Alles ok';
// send an email
}
$errors = array();
$validation = $this->get('validator')->validate($form);
foreach ($validation as $error) {
$errors[$error->getPropertyPath()] = $error->getMessage();
}
$response = new Response();
$response->setContent(json_encode(array(
'form_data' => $data,
'errors' => $errors,
)));
$response->headers->set('Content-Type', 'application/json');
return $response;
}
}
CSRF在config.yml
禁用。表單沒有綁定到實體類。提交表格後,我在控制檯中的下列對象:
{
data: Object,
status: 200,
config: Object,
statusText: "OK"
}
的重要組成部分,是data: Object
:
{
form_data: {
contactPerson: null,
email: null,
message: "infoscreenForm",
file: null
},
errors : {
children[contactPerson].data = "This value should not be blank",
children[email].data = "This value should not be blank"
}
}
這發生在我提交表單,在字段中輸入一些值。看起來提交的數據沒有綁定到控制器中的表單。我可能錯過了一些東西,但我卡在這裏,不知道如何繼續。我試着用$form->bind($request)
,$form->handleRequest($request)
和其他一些東西,但它沒有奏效。即使我單獨綁定這些字段,我仍然沒有在表單中獲得它們的值。
有人可以幫我。
在此先感謝。
是的,這樣做的伎倆。我還必須用'$ form-> bind($ request)'綁定表單,現在我得到了這些值。非常感謝你! большоеспасибо! – cezar