erros與python中的字典鍵和值轉換

Question

我正在爲Python中的埃及分部編寫代碼。 什麼是埃及分部 例如，通過17 3.

Powers of two column  divisor doubling column 

     2^0 = 1      3 
     2^1 = 2      6 
     2^2 = 4      12 
     2^3 = 8      24 
    24>17 so we can stop. 

分縱觀3,6的組合，和12我們看到，12 + 3 = 15是 我們似乎可以得到不最接近超過17.

現在我得到了上面的輸出，但我無法得到商，因爲我使用字典，它給了我一個錯誤。

import sys 
astring = raw_input("Enter the A integer: ") #accepting input 
a = int(astring)        #dividend 
bstring = raw_input("Enter the B integer: ") # accepting input 
b = int(bstring)        #divisor 
Egyptian_Division_dict = {}     # initiating dictionary 
i =0           # setting counter for 2^i 
x =0 
z =0 
#k = 0 #m = 0 
list_of_divisor = [] 
list_of_two = [] 
while i< a: 
    k = 2**i 
    m = k*b 
    if m < a: 
     list_of_divisor.append (k) 
     list_of_two.append(m) 
    i += 1 
for i in range(len(list_of_divisor)): 
    Egyptian_Division_dict[list_of_divisor[i]] = list_of_two[i] 
list_of_divisor = sorted(list_of_divisor, reverse=True) 
list_of_two = sorted(list_of_two, reverse=True) 
print "printing dictionary" 
for keys,values in sorted (Egyptian_Division_dict.items(),reverse = True): 
    print (keys), (values) 
    #if z == a: 
     # z=+value 
     #print z 
rough = 0 
quetient = 0 
for keys in sorted (Egyptian_Division_dict.items(),reverse = True): 
    #Egyptian_Division_dict[keys] = str([keys]) 
    #Egyptian_Division_dict[values] = str([values]) 
    w = keys 
    z = values 
    if rough + z <a: 
     rough = rough+z 
     quetient = quetient + w 
    else : 
     print quetient 

錯誤：

Enter the A integer: 44                                    
Enter the B integer: 4                                    
printing dictionary                                     
8 32                                         
4 16                                         
2 8                                         
1 4                                         
Traceback (most recent call last):                                 
    File "main.py", line 39, in <module>                                
    quetient = quetient + w                                   
TypeError: unsupported operand type(s) for +: 'int' and 'tuple' 

如何刪除這個錯誤？

Answer 1

在你的第二個循環，你分配(key, value)元組到單個變量，keys：

for keys in sorted (Egyptian_Division_dict.items(),reverse = True): 

然後，您嘗試在元組添加到一個整數：

quetient = 0 

# in the loop 
w = keys 
quetient = quetient + w 

這是引發異常的最後一行。

您似乎忘記在該循環中包含values變量;將它放回至少會使keys再次成爲一個關鍵：

for keys, values in sorted (Egyptian_Division_dict.items(),reverse = True): 

隨着這種變化，對於quetient值確實加起來15：

>>> Egyptian_Division_dict = {8: 32, 4: 16, 2: 8, 1: 4} 
>>> rough = 0 
>>> quetient = 0 
>>> for keys, values in sorted (Egyptian_Division_dict.items(),reverse = True): 
...  w = keys 
...  z = values 
...  if rough + z <a: 
...   rough = rough+z 
...   quetient = quetient + w 
...  else : 
...   print quetient 
... 
>>> quetient 
15